The product of a variable and a number should be a variable and a number. I think A, b, and d are the answer because they all comprise of a variable (c, t, j) and a number (11, 1/2, 4). C only provides two numbers and no variable
Answer:
4546442
Step-by-step explanation:
you need to go to school
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When evaluating b^2c^-1 for b=8 and c=4, the answer is -16
E = b^2c–1
x-a = 1/xa
E = b^2c - 1
= 8^2 x (-4)-1
= 64/-4
= -16
Factor the equation so...
(r^2-pr) and (p^2q-pqr)
Factor out (r^2-pr) = r(r-p)
Factor out (p^2q-pqr) = pq(p-r)
Add a negative to r(r-p) to make it -r(p-r)
(pq-r)(p-r) is the answer... I'm sorry I can't explain things well, but I tried.
