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zvonat [6]
3 years ago
14

Y = 4x - 5 y = 3 Solve system of equations

Mathematics
1 answer:
kifflom [539]3 years ago
5 0
3=4x-5
3+5=4x
8=4x
X=8/4=2

X=2 and Y=3
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Find the equation of the line through point (2,2) and parallel to y=x+4. Use a forward slash (i.e.”/“) for fractions (e.g. 1/2 f
aleksandr82 [10.1K]

Answer:

The equation of the line is, y = x

Step-by-step explanation:

The constraints of the required linear equation are;

The point through which the line passes = (2, 2)

The line to which the required line is parallel = y = x + 4

Two lines are parallel if they have the same slope, therefore, we have;

The slope of the line, y = x + 4 is m = 1

Therefore, the slope of the required line = 1

The equation of the required lime in point and slope form becomes;

y - 2 = 1 × (x - 2)

∴ y = x - 2 + 2 = x

The equation of the required line is therefore, y = x

5 0
3 years ago
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I would say the answer would be 105 
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What is the single half digit number of 11
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There is no whole number that is half of 11 but the half number is 5.5
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3 years ago
12. Let yo = O. Write parametric equations to represent the path of the ballsthrown by Sami and T'Aisha given the following cond
ira [324]

SOLUTION:

We want to write the x and y parametric equation for Sami and T'Aisha given their following data.

\begin{gathered} Sami:v_0=15\frac{ft}{s},\theta=35^o,y_0=5.4ft \\ T^{\prime}Aisha:v_0=19\frac{ft}{s},\theta=50^o,y_o=5.8ft \\ x_0=0 \end{gathered}

The parametric equations for x and y are given by;

\begin{gathered} x(t)=x_0+(v_0cos\theta)t \\ y(t)=y_0+(v_0sin\theta)t+0.5gt^2 \end{gathered}

Inserting, the values, we have; For Sami;

\begin{gathered} Sami: \\ x\left(t\right)=15cos35t, \\ y\left(t\right)=5.4+15sin35t-16t^2 \end{gathered}

For T'Aisha;

\begin{gathered} T^{\prime}Aisha: \\ x\left(t\right)=19cos50t, \\ y\left(t\right)=5.8+19sin50t-16t^2 \end{gathered}

4 0
1 year ago
__ __ Calcula (a+b), si la suma de los complementos aritmeticos de ab y ba es 24
IceJOKER [234]

Respuesta:

dieciséis

Explicación paso a paso:

100-ab - - - - (1)

100-ba - - - - (2)

Sumando (1) y (2) sumas hasta 24

100-ab + 100-ba = 24

100 + 100 - ab - ba = 24

200- (10a + b) - (10b + a) = 24

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176 = 11 (a + b)

176/11 = a + b

16 = (a + b)

6 0
3 years ago
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