The possible digits are:
5, 6, 7, 8 and
9. Let's mark the case when the locker code begins with a prime number as
A and the case when <span>the locker code is an odd number as
B. We have
5 different digits in total,
2 of which are prime (
5 and
7).
First propability:
</span>

<span>
By knowing that digits don't repeat we can say that code is an odd number in case it ends with
5, 7 or
9 (three of five digits).
Second probability:
</span>
92,500 x 6,800,000,000
6.29e+14
Mark brainliest please
Hope this helps you
Answer:
4b^-1
Step-by-step explanation:
16a/4 = 4a
4a/a = 4
4/b = 4b^-1