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3 years ago

You can complete 2 math problems in 60 seconds. How long will it take you to

Mathematics

1 answer:

mariarad [96]3 years ago

4 0

Answer:

1080

Step-by-step explanation:

You can add 60 18 times to get 1080 seconds. (60+)

I hope I helped (:

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True or false? Postulates are statements that are accepted without question or justification

ale4655 [162]

<span>True, as a postulate is the assumption of existence.</span>

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3 years ago

Read 2 more answers

If X is a binomial random variable associated with a binomial experiment with

Makovka662 [10]

For a binomial distribution over $n$ trials and with success probability $p$ , the mean $\mu$ and standard deviation $\sigma$ ar such that

$\begin{cases}\mu=np\\\sigma=\sqrt{np(1-p)}\end{cases}$

$6=\sqrt{np(1-p)}\implies np-np^2=36$
$54=np\implies54-54p=36\implies p=\dfrac13$
$54=\dfrac n3\implies n=162$

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3 years ago

PLZ HELP ASAP A candy machine contains spherical candies. Each candy is solid and has a diameter of 0.25 in.

NikAS [45]

Each candy has a volume of about 8.18 * 10^-3 which is simplified to .00818

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4 years ago

Jack brought a keyboard priced at $183.60 the sales tax was found by multiplying the price of the keyboard by 0.05 what was the

blondinia [14]

Answer:

192.78‬

Step-by-step explanation:

maybe just use a calculator?????

5 0

4 years ago

Use green’s theorem to evaluate

Georgia [21]

By Green's theorem (all the conditions are met), we have

$\displaystyle \int_C \sqrt y \, dx + \sqrt x \, dy = \iint_D \frac{\partial(\sqrt x)}{\partial x} - \frac{\partial(\sqrt y)}{\partial y} \, dx \, dy$

where D is the interior of the path C, or the set

$D = \left\{ (x, y) : 0 \le y \le \dfrac{x^2}2 \text{ and } 0 \le x \le 2 \right\}$

So, the line integral reduces to the double integral,

$\displaystyle \frac12 \int_0^2 \int_0^{\frac{x^2}2} x^{-\frac12} - y^{-\frac12} \, dy \, dx$

$\displaystyle = \frac12 \int_0^2 x^{-\frac12}\left(\frac{x^2}2\right) - 2\left(\frac{x^2}2\right)^{\frac12} \, dx$

$\displaystyle = \frac12 \int_0^2 \frac12 x^{\frac32} - \sqrt 2 \, x \, dx$

$\displaystyle = \frac14 \int_0^2 x^{\frac32} - 2\sqrt 2 \, x \, dx$

$\displaystyle = \frac14 \left(\frac25\cdot2^{\frac52} - \sqrt2\cdot2^2\right) = \boxed{-\frac{3\sqrt2}5}$

5 0

2 years ago