First we gather all the information we have about the amount of miles that Carolyn runs:
Monday, Wednesday, Friday: 4 1/2 miles
Tuesday, Saturday: 2 3/4 miles
And the question is the amount of miles that she runs in 4 weeks.
So lets begin by calculating the amount of miles she runs in one week, then we just multiply by 4 and we'll have the final answer.
So, we have to add 4 1/2 three times (Monday, Wed, Friday), and 2 3/4 two times (Tuesday, Sat):
1 week Miles = 4 1/2 + 4 1/2 + 4 1/2 + 2 3/4 + 2 3/4
lets add the whole parts and the fraction parts apart:
1 week Miles = (4 + 4 + 4 + 2 + 2) + (1/2 + 1/2 + 1/2 + 3/4 + 3/4)
1 week <span>Miles = (16) + (3/2 + 6/4)
</span>we can reduce the last fraction:
1 week <span>Miles = (16) + (3/2 + 3/2)
</span>1 week <span>Miles = (16) + (6/2)
</span>1 week <span>Miles = (16) + (3)
</span>1 week <span>Miles = 19
</span>therefore Carolyn runs 19 miles each week, so for 4 weeks we have to add 19 four times or multiply it by 4, is the same:
4 weeks <span>Miles = 4*19
</span>4 weeks <span>Miles = 76
hence Carolyn runs 76 miles in 4 weeks.</span>
You would do 129/3 so he drove 43 miles per hour
Answer:
90 inches squared
Step-by-step explanation:
To do this you would first find the area of the 2 triangles shown on the side so we would do 5 times 2 divided by 2 since that is how we solve this problem so we would get 5 inches squared for the 2 triangles then we would find the area of the square which is 100 since it is a 10 by 10 then you would subtract 5+5 by 100 which is 90 so 90 inches squared would be the answer
Answer:
y = 2x − 1
Step-by-step explanation:
By eliminating the parameter, first solve for t:
x = 4 + ln(t)
x − 4 = ln(t)
e^(x − 4) = t
Substitute:
y = t² + 6
y = (e^(x − 4))² + 6
y = e^(2x − 8) + 6
Taking derivative using chain rule:
dy/dx = e^(2x − 8) (2)
dy/dx = 2 e^(2x − 8)
Evaluating at x = 4:
dy/dx = 2 e^(8 − 8)
dy/dx = 2
Writing equation of line using point-slope form:
y − 7 = 2 (x − 4)
y = 2x − 1
Now, without eliminating the parameter, take derivative with respect to t:
x = 4 + ln(t)
dx/dt = 1/t
y = t² + 6
dy/dt = 2t
Finding dy/dx:
dy/dx = (dy/dt) / (dx/dt)
dy/dx = (2t) / (1/t)
dy/dx = 2t²
At the point (4, 7), t = 1. Evaluating the derivative:
dy/dx = 2(1)²
dy/dx = 2
Writing equation of line using point-slope form:
y − 7 = 2 (x − 4)
y = 2x − 1
