Ask question

Ask question

All categories

3 years ago

5

3,219 millimeters of of water and 185 millimeters of orange syrup are mixed to make orange juice. about how many orange juice wi

ll there be?

1 answer:

Arte-miy333 [17]3 years ago

3 0

3,219+185 millimeters is 3404 millimeters of orange juice.
Hope this helped.

You might be interested in

DAY 3 pleaseeee helllpp

Natali5045456 [20]

The answer is c. 3,600

3 0

3 years ago

Read 2 more answers

Help me with number 10 pleaseeeeeeeeee

valina [46]

Answer:

4' - 9.64

Step-by-step explanation:

Total rise = 2' - 7"

Total run = 3' - 9"

Converting to inches :

1' = 12" ; 1 feet = 12 inches

2' = 2 * 12 = 24"

3' = 3 * 12 = 36"

Total rise = 24" + 7" = 31"

Total run = 36" + 9" = 45"

Length of stringer = hypotenus

Hypotenus = √(total rise² + total run²)

Hypotenus = √(31² + 45²)

Hypotenus = 54.644304"

= 4' - 9.64"

6 0

2 years ago

F(x)=2x^2-3x+7 evaluate f(-2)

Vilka [71]

Answer:

Step-by-step explanation:

Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?

Let p(x)=kpx+dp and q(x)=kqx+dq than

f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7

p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7

(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)

So you want:

−2kpk2q=0

and

kpkq=−1

and

2kpd2p−3kpdq+7=0

Now I amfraid this doesn’t work as −2kpk2q=0 that either kp or kq is zero but than their product can’t be anything but 0 not −1 .

Answer: there are no such linear functions.

6 0

2 years ago

48 is 9 less than 3 times a number. What is the number?

Kamila [148]

19 x 3 = 57 57 - 9 = 48 Your answer is 19.

4 0

3 years ago

Read 2 more answers

What is the value of x for part A and part B

GuDViN [60]

Part A :

So the two sides are equivalent,

$9x - 18 = 3x$

Solve for x and get 3.

~~

Answer : x = 3

~~

Part B :

To find JM, simply substitute x for 3 and solve,

$9(3) - 18$
$27 - 18 = 9$
~^

Answer : JM = 9

~~

I hope that helps you out!!

Any more questions, please feel free to ask me and I will gladly help you out!!

~Zoey

5 0

2 years ago