Answer:
No solution
Step-by-step explanation:
Muah ha ha ha ha ha ha
Answer:
When the volume of a gas in a container varies inversely with the pressure on the gas and a container of nitrogen has a volume of 29.5 litres with 2000 psi. So, if the tank has a 14.7 psi pressure, then the volume of the tank would be 4013.6 litres.
Step-by-step explanation:
- The volume of a gas in a container varies inversely with the pressure on the gas. If a container of nitrogen has a volume of litres with psi, what is the volume if the tank has a psi pressure.
- Calculate the volume to the nearest whole number.
- Use the given values and calculate the proportionality constant as well as required solution.
Step 1 of 2
Write the inversely proportionality relation between the volume and pressure of a gas in container.
![$v \propto \frac{1}{p}$](https://tex.z-dn.net/?f=%24v%20%5Cpropto%20%5Cfrac%7B1%7D%7Bp%7D%24)
Where volume is represented by v and pressure is represented by p.
Remove the proportionality and place a constant say k.
![$v=\frac{k}{p}$](https://tex.z-dn.net/?f=%24v%3D%5Cfrac%7Bk%7D%7Bp%7D%24)
Substitute the given values of nitrogen that v=29.5 and
p=2000 and calculate the value of k from above equation.
![$$\begin{aligned}&29.5=\frac{k}{2000} \\&\Rightarrow k=29.5 \times 2000 \\&\Rightarrow k=59000\end{aligned}$$](https://tex.z-dn.net/?f=%24%24%5Cbegin%7Baligned%7D%2629.5%3D%5Cfrac%7Bk%7D%7B2000%7D%20%5C%5C%26%5CRightarrow%20k%3D29.5%20%5Ctimes%202000%20%5C%5C%26%5CRightarrow%20k%3D59000%5Cend%7Baligned%7D%24%24)
Step 2 of 2
Substitute the value p=14.7 and above calculated k value in the equation
![$$\begin{aligned}&v=\frac{k}{p} . \\&v=\frac{59000}{14.7} \\&\Rightarrow v=4013.6\end{aligned}$$](https://tex.z-dn.net/?f=%24%24%5Cbegin%7Baligned%7D%26v%3D%5Cfrac%7Bk%7D%7Bp%7D%20.%20%5C%5C%26v%3D%5Cfrac%7B59000%7D%7B14.7%7D%20%5C%5C%26%5CRightarrow%20v%3D4013.6%5Cend%7Baligned%7D%24%24)
Answer:
10 for each side so 40 tiles
Step-by-step explanation:
1/18 as a decimal is 0.055555555555556 because you divide one by eighteen and get that number.
Hope this helped!
I don’t know but I’ll try to figure it out