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Sonbull [250]
3 years ago
5

Two times a number is the result when 7 times the same number is taken away from 99. What is the number?

Mathematics
1 answer:
OLEGan [10]3 years ago
7 0

2x=99-7x

9x=99

x = 11


2x11 = 22

99-&7*11) = 22


 so the number is 11

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Can someone help me with number 8 plz
statuscvo [17]
We have the following equation:
 h (t) = - 16t ^ 2 + 161t + 128
 We substitute the value of h (t) = 170:
 170 = -16t ^ 2 + 161t + 128
 We rewrite the equation:
 -16t ^ 2 + 161t + 128 - 170 = 0
 -16t ^ 2 + 161t - 42 = 0
 We look for the roots of the equation:
 t1 = (161/32) + root (23233) / 32
 t2 = (161/32) - root (23233) / 32
 Answer:
 
The object is 170 feet off the ground at the following times:
 
t1 = (161/32) + root (23233) / 32
 
t2 = (161/32) - root (23233) / 32
7 0
3 years ago
Topic: The Quadratic Formula
Finger [1]

Answer:

Step-by-step explanation:

The quadratic formula for a equation of form

ax²+bx + c = 0 is

x= \frac{-b +- \sqrt{b^2-4ac} }{2a}

For the first equation,

x²+3x-4=0,

we can match that up with the form

ax²+bx + c = 0

to get that

ax² =  x²

divide both sides by x²

a=1

3x = bx

divide both sides by x

3 = b

-4 = c

. We can match this up because no constant multiplied by x could equal x² and no constant multiplied by another constant could equal x, so corresponding terms must match up.

Plugging our values into the equation, we get

x= \frac{-3 +- \sqrt{3^2-4(1)(-4)} }{2(1)} \\= \frac{-3+-\sqrt{25} }{2} \\ = \frac{-3+-5}{2} \\= -8/2 or 2/2\\=  -4 or 1

as our possible solutions

Plugging our values back into the equation, x²+3x-4=0, we see that both f(-4) and f(1) are equal to 0. Therefore, this has 2 real solutions.

Next, we have

x²+3x+4=0

Matching coefficients up, we can see that a = 1, b=3, and c=4. The quadratic equation is thus

x= \frac{-3 +- \sqrt{3^2-4(1)(4)} }{2(1)}\\= \frac{-3 +- \sqrt{9-16} }{2}\\= \frac{-3 +- \sqrt{-7} }{2}\\

Because √-7 is not a real number, this has no real solutions. However,

(-3 + √-7)/2 and (-3 - √-7)/2 are both possible complex solutions, so this has two complex solutions

Finally, for

4x² + 1= 4x,

we can start by subtracting 4x from both sides to maintain the desired form, resulting in

4x²-4x+1=0

Then, a=4, b=-4, and c=1, making our equation

x=\frac{-(-4) +- \sqrt{(-4)^2-4(4)(1)} }{2(4)} \\= \frac{4+-\sqrt{16-16} }{8} \\= \frac{4+-0}{8} \\= 1/2

Plugging 1/2 into 4x²+1=4x, this works as the only solution. This equation has one real solution

7 0
3 years ago
Is the number 5.2 x 102 greater than 1 or smaller than 1?
elena55 [62]
It’s b I did this lesson before hope that helps
8 0
2 years ago
Read 2 more answers
Find the measure of
Furkat [3]

Answer:

B. 30

Step-by-step explanation:

3x + 2x + x = 180 (angle sum of a triangle is 180)

6x = 180

x = 30

6 0
2 years ago
Read 2 more answers
A=1/2bh. A=200ft. H=10. What is b
Svetllana [295]

Answer:

B= \frac{2A}{H}

Step-by-step explanation:

If you noticed, A= \frac{1}{2}BH is the formula for finding the area for a triangle. Your goal is to get B by it's self. Your first step will be to clear of the fraction first, so you will multiply both sides by 2.   2(A)=2(\frac{1}{2}BH).    On the left, you have 2×A= On the right side, you have     2(\frac{1}{2}BH),     but since you have a number in the equation, you will only use 2×\frac{1}{2}. To solve  2×\frac{1}{2}, you will cnacel out both 2's and you have 1. 1×BH will still equal BH, so you are now left will B×H.

(Your new equation looks like this by the way).    2A=BH

Since you need to get B by its self, the way to clear the H away from the B is by dividing.  You will now divide the B and H aswell as 2A and H. (It will look like this) \frac{2A}{H} = \frac{BxH}{H} . (Again when you have the same number or letter, you cross it out. When you divide, you won't change anything on the left side, and all you have to do on the right id to cross out the H next to the B and cross out the H on the bottom of the equation). You should be left with \frac{2A}{H} = B. Now you can turn it around for your final answer. B= \frac{2A}{H}.

Please let me know if i helped, how I did, and if you have any questions.

3 0
3 years ago
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