Mrs. Reid is going on a trip. She has 9 book that she hasn't ready yet, but she wants to bring only 3 on the trip.
1 answer:
The way you work this out is by thinking about the odds of each singular event, then finding the overall odds based on the individual odds.
The number of different books Mrs. Reid can choose is 9, so the first number is 9.
Mrs. Reid has picked one book so far, so now she has (1 - 9) = 8 books to choose from.
The of different books Mrs. Reid can choose now is 8, so your second number is 8.
Mrs. Reid has picked 2 book thus far, so now there are (2 - 9) = 7 books to choose from.
The of different books Mrs. Reid can choose now is 7, so your second number is 7.
To get the total number of different choices, multiply all the singular events together:
The number of different books Mrs. Reid can choose is 9, so the first number is 9.
Mrs. Reid has picked one book so far, so now she has (1 - 9) = 8 books to choose from.
The of different books Mrs. Reid can choose now is 8, so your second number is 8.
Mrs. Reid has picked 2 book thus far, so now there are (2 - 9) = 7 books to choose from.
The of different books Mrs. Reid can choose now is 7, so your second number is 7.
To get the total number of different choices, multiply all the singular events together:
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Answer:
1) -184
2) 13-3(
)+4
Step-by-step explanation:
For problem number 1, Let's start by substituting all the x's for -3
So the equation will look like
p(-3)=-
+7(-3)-10
Now, lets simplify by solving the exponents
First we'll do which equals -27
Now we'll do which equals 9
So now our equation looks like
p(-3)=4(-27)-5(9)+7(-3)-10
Now, we are going to multiply all these numbers
First 4(-27) which equals -108
Now -5(9) which equals -45
And finally 7(-3) which equals -21
Now our equation looks like
p(-3)= -108-45-21-10
Now we can solve
-108-45-21-10=-184