Answer:
all objects in the universe.
Answer:
Displacement of Mr. Llama: Option D. 0 miles.
Explanation:
The magnitude of the displacement of an object is equal to the distance between its final position and its initial position. In other words, as long as the initial and final positions of the object stay unchanged, the path that this object took will not affect its displacement.
For Mr. Llama:
- Final position: Mr. Llama's house;
- Initial position: Mr. Llama's house.
The distance between the final and initial position of Mr. Llama is equal to zero. As a result, the magnitude of Mr. Llama's displacement in the entire process will also be equal to zero.
Answer:
One should draw a diagram showing the placement of the charges.
When both charges of -Q are placed there will be no force in the vertical direction because of cancellation of forces.
A line from one corner of the square to the other makes an angle of 45 degrees,
2 cos 45 deg will be the force due to one charge.
2 * .707 = 1.41 N
So for both charges the force is (horizontal, vertical is zero)
2 * 1.41 = 2.82 N
b) is correct
Answer:
1 friction produces heat which damages the moving part of a machine
2 a lot of energy is wasted In overcoming the friction before an object starts moving
3 friction produces wear and tear on the contacting surfaces
Answer:
Time = 12.27seconds
Explanation:
Given
Speed = 25miles/hour
Distance = 150 yards = 150(0.000568182)miles
Distance (in miles) = 0.0852273miles
Get the time
Speed = Distance/Time
Time = Distance/Speed
Time = 0.0852273/25
Time = 0.0034hours
Time = 0.0034 * 3600secs
Time = 12.27seconds