Calculate the average velocity of object over the first 10 seconds of the trip
1 answer:
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Answer:
47 miles
Explanation:
From the diagrammatic representation below;we can observe the illustration of the question.
after two hours;
The first ship = 16 miles per hour × 2 hours = 32 hours
the second ship = 11 miles per hour × 2 hours = 22 hours
to solve for ΔQPR in the diagram; we have;
∠ P = 13° + (2nd quadrant) + 15°
∠ P = 13° + 90° + 15°
∠ P = 118°
To solve for the distance apart the two ship, we can see from the diagram that it is "p". So, using cosine rule; we have:
p² = q² + r² - 2qr Cos P
p² = 22² + 32² - 2(22)(32) Cos 118°
p² = 484 + 1024 - (1408) (-0.4695)
p² = 1508 + 661.056
p² = 2169.056
p =
p = 46.5731252
p ≅ 47 miles
∴ The ships will be 47 miles far apart after 2 hours.
Answer:
P= 454.11 N
Explanation:
Since P is the only horizontal force acting on the system, it can be defined as the product of the acceleration by the total mass of the system (both cubes).
The friction force between both cubes (F) is defined as the normal force acting on the smaller cube multiplied by the coefficient of static friction. Since both cubes are subject to the same acceleration:
In order for the small cube to not slide down, the friction force must equal the weight of the small cube:
The smallest magnitude that P can have in order to keep the small cube from sliding downward is 454.11 N