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Reil [10]
3 years ago
15

Plzz I need help due today!!!!

Mathematics
1 answer:
Rufina [12.5K]3 years ago
4 0
A is increasing , b is maximum , c is decreasing, and d is minimum
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Pls help its due today
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Step-by-step explanation:

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Solve this <br><br> 4( x + 4)=
Leokris [45]

Answer:

4x + 16 - simplified

Step-by-step explanation:

5 0
3 years ago
Which graph represents a function?
salantis [7]

Answer:

It is the answer closest to the right. The one with a straight line.

Step-by-step explanation:

Because it is a function if there is only one dot per line vertically. The others have either 2 or more dots per line vertically.

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3 years ago
Can anyone tell me how to do this?
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Step-by-step explanation:

8 0
3 years ago
Calculate the range, population variance, and population standard deviation for the following data set. If necessary, round to o
Roman55 [17]

Answer:

Range = 11-2=9

\mu = \frac{2+3+4+5+6+7+8+9+10+11}{10}=6.5

\sigma^2 =8.25 \approx 8.3

\sigma = \sqrt{8.25}= 2.87 \approx 2.9

Step-by-step explanation:

Assuming this question: "Calculate the range, population variance, and population standard deviation for the following data set. If necessary, round to one more decimal place than the largest number of decimal places given in the data. 2,3,4,5,6,7,8,9,10,11 "

Solution to the problem

The range is defined as Range = Max -Min and if we replace we got:

Range = 11-2=9

Now we can calculate the population mean with this formula:

\mu =\frac{\sum_{i=1}^n X_i}{N}

And if we replace we got:

\mu = \frac{2+3+4+5+6+7+8+9+10+11}{10}=6.5

The population variance is given by:

\sigma^2 = \frac{\sum_{i=1}^n (X_i -\mu)^2}{N}

And after replace we got: \sigma^2 =8.25 \approx 8.3

And the population standard deviation would be just the square root of the variance and we got:

\sigma = \sqrt{8.25}= 2.87 \approx 2.9

4 0
4 years ago
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