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3 years ago

Plzz I need help due today!!!!

Mathematics

1 answer:

Rufina [12.5K]3 years ago

4 0

A is increasing , b is maximum , c is decreasing, and d is minimum

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In golf, a score of 0 is called even par. A score of 2 under par is written as -2. A score of 4 over par is written as +4 or 4.

patriot [66]

6 under par is written as -6

2 over par is written as 2

even par is written as 0

Total score: add all the numbers together:

-6 + 2 + 0 + 0 = -4 ( 4 under par).

7 0

3 years ago

Fill in the blank to make equivalent rational expressions

siniylev [52]

Answer:

I think the answer is 7-u hope this helps

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3 years ago

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Solve for t. 3t - 18 = 4(-3-3/4t). t=

Alex73 [517]

Answer:T=1

Step-by-step explanation:

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3 years ago

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If f is a linear function, f(k)=16 and f(-k)= -4 then what is the value of f(0)?

ira [324]

f(0) = ( f(k) +f(-k) ) / 2

f(0) = (16 - 4) / 2

f(0) = 12 / 2

f(0) = 6 → ANSWER

*Remember that f(0) = m(0) + n = n

If we have f(x) = mx + n, then:

f(k)= mk + n and f(-k)= -mk + n

If we add them:

f(k) + f(-k)

= mk + n -mk + n

= 2n

= 2f(0)

So we conclude that:

f(0) = [f(k) + f(-k)] / 2

3 0

3 years ago

Erica is a sheep farmer. She is having a problem with wolves attacking the flock. She starts with an initial 200 sheep and notic

Free_Kalibri [48]

The equation for the situation is $y=200(\frac{2}{3})^{x}$

It will take around 9 years for her to have around 5 sheep

Step-by-step explanation:

The exponential decay growth/decay equation is $y=a(b)^{x}$ , where

a is the initial value
b is the growth/decay factor
If b > 1, then it is a growth factor
If 0 < b < 1, then it is a decay factor

Erica is a sheep farmer. She is having a problem with wolves attacking the flock. She starts with an initial 200 sheep and notices that the population is two-thirds of the previous year

∵ The population is decreased

∴ The equation is decay

∵ The population is two-thirds of the previous year

∴ The decay factor is $\frac{2}{3}$

∵ She starts with an initial 200 sheep

∴ the initial value is 200

∵ The decay equation is $y=a(b)^{x}$ , where y represent the

population in x years

∵ a = 200

∵ b = $\frac{2}{3}$

∴ $y=200(\frac{2}{3})^{x}$

The equation for the situation is $y=200(\frac{2}{3})^{x}$

∵ The population after x years is around 5 sheep

- Substitute y by 5 to find x

∵ $5=200(\frac{2}{3})^{x}$

- Divide both sides by 200

∴ $0.025=(\frac{2}{3})^{x}$

- Insert ㏒ for both sides

∴ $log(0.025)=log(\frac{2}{3})^{x}$

∴ $log(0.025)=xlog(\frac{2}{3})$

- Divide both sides by $log(\frac{2}{3})$

∴ 9.098 = x

∴ x is around 9 years

It will take around 9 years for her to have around 5 sheep

Learn more:

You can learn more about the equation in brainly.com/question/10666510

#LearnwithBrainly

8 0

3 years ago