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zepelin [54]
2 years ago
5

Solve the system graphically: b x−y=0 2x+3y=−5 x= y=

Mathematics
1 answer:
vlabodo [156]2 years ago
6 0

Answer:

(-1,-1)

Step-by-step explanation:

x=y

2x+3x=-5

x=-1

y=-1

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Question : In the given figure , ∆ APB and ∆ AQC are equilateral triangles. Prove that PC = BQ.
lorasvet [3.4K]

Answer:

See Below.

Step-by-step explanation:

We are given that ΔAPB and ΔAQC are equilateral triangles.

And we want to prove that PC = BQ.

Since ΔAPB and ΔAQC are equilateral triangles, this means that:

PA\cong AB\cong BP\text{ and } QA\cong AC\cong CQ

Likewise:

\angle P\cong \angle PAB\cong \angle ABP\cong Q\cong \angle QAC\cong\angle ACQ

Since they all measure 60°.

Note that ∠PAC is the addition of the angles ∠PAB and ∠BAC. So:

m\angle PAC=m\angle PAB+m\angle BAC

Likewise:

m\angle QAB=m\angle QAC+m\angle BAC

Since ∠QAC ≅ ∠PAB:

m\angle PAC=m\angle QAC+m\angle BAC

And by substitution:

m\angle PAC=m\angle QAB

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\angle PAC\cong \angle QAB

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\Delta PAC\cong \Delta BAQ

And by CPCTC:

PC\cong BQ

5 0
2 years ago
Read 2 more answers
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