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3 years ago

Wpisz w okienka odpowiednie potęgi

Mathematics

2 answers:

allochka39001 [22]3 years ago

7 0

Answer:

what is the question bro

Tamiku [17]3 years ago

4 0

Answer:

English? and for that matter

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Simplify 4x5p:) thanks whoever answers receives points

bazaltina [42]

Answer:

20xp

Step-by-step explanation:

7 0

3 years ago

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If sec= 5/3 and the terminal point determined by is in quadrant 4, then

OLga [1]

$\bf sec(\theta)=\cfrac{1}{cos(\theta)}\\\\
-----------------------------\\\\
sec(\theta)=\cfrac{5}{3}\implies \cfrac{1}{cos(\theta)}=\cfrac{5}{3}\implies \cfrac{3}{5}=cos(\theta)
\\\\\\
\textit{now, }\theta\textit{ is in the 4th quadrant}$

so... notice the picture below, the angle in the fourth quadrant
now... notice, the cosine is just the distance the angle makes with the x-axis
so... using the pythagorean theorem, get the opposite side, from that triangle, keeping in mind that, "y" is negative in the 4th quadrant

once you get "y", get any other trigonometry value you need :)

7 0

3 years ago

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HELP! WILL GIVE BRANLIEST!

Brrunno [24]

6x+x-8=90 because right angle
7x=98 combine like terms
7x/7=98/7
X=14
m<1=6*14=84
m<2=14-8=6

8 0

2 years ago

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If anybody could help with this question I would appreciate it so much!!

elena-14-01-66 [18.8K]

Answer:

d=7

Step-by-step explanation:

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3 years ago

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Find the second derivative of 2x^3-3y^2=8

Umnica [9.8K]

Answer:

$\frac{d^2y}{dx^2}=\frac{x(2y-x^3)}{y^3}$

Step-by-step explanation:

Find the first implicit derivative using implicit differentiation

$2x^3-3y^2=8\\\\6x^2-6y\frac{dy}{dx}=0\\ \\-6y\frac{dy}{dx}=-6x^2\\ \\\frac{dy}{dx}=\frac{x^2}{y}$

Use the substitution of dy/dx to find the second derivative (d²y/dx²)

$\frac{d^2y}{dx^2}=\frac{(y)(2x)-(x^2)(\frac{dy}{dx})}{y^2}\\ \\\frac{d^2y}{dx^2}=\frac{2xy-(x^2)(\frac{x^2}{y})}{y^2}\\\\\frac{d^2y}{dx^2}=\frac{2xy-\frac{x^4}{y}}{y^2}\\\\\frac{d^2y}{dx^2}=\frac{x(2y-x^3)}{y^3}$

5 0

3 years ago

Wpisz w okienka odpowiednie potęgi​

Wpisz w okienka odpowiednie potęgi