rules to find :- 1 All non zeroes number are significant
2 if zero proceeding the decimal point also work as non zero figure
3 zero are following the decimal point and proceeding the first non zero digit
4 Zero in between 2 non zero digits are also significant
5 if 1 zero follow the decimal point
790 :- 2 significant figures
0.0391 :- 3 significant figures ( follow 3 rule)
81.05 :- 4 significant figures ( rule 4)
0.000001 :- 1 significant figure
8546 :- 4 significant figures
79.0 :- 3 significant ( rule 5)
The simplified rational expression is (y - 3)/(y + 3). Where y ≠ -3.
<h3>How to simplify a rational expression?</h3>
A rational expression is in the p/q form. Where p and q are polynomial functions.
To simplify this rational equation,
- Factorize the polynomials in both numerator and denomiantor.
- Cancel out common factors if any.
- If the denominator and the numerator have no common factors except 1, then that is said to be the simplest form of the given rational expression.
<h3>Calculation:</h3>
The given rational equation is

Factorizing the expression in the numerator:
y² - 12y + 27 = y² - 9y - 3y + 27
⇒ y(y - 9) - 3(y - 9)
⇒ (y - 3)(y - 9)
Factorizing the expression in the denominator:
y² - 6y - 27 = y² - 9y + 3y - 27
⇒ y(y - 9) + 3(y - 9)
⇒ (y + 3)(y - 9)
Since they have (y - 9) as the common factor, we can simplify,

⇒ (y - 3)/(y + 3) where y ≠ -3(denomiantor)
Here there are no more common factors except 1; this is the simplest form of the given rational expression.
Learn more about simplifying rational expressions here:
brainly.com/question/1928496
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Step-by-step explanation:
To me yes.
Algebra is mostly memorization. If you know the formulas and know how to apply it, you should do good.
I say use this. Algebra topics are like building on top each other.
Heart of Algebra:
- Review what the purpose of x in algebra.
- Then learn things like combining like terms, and solving for x.
- Since you know the basics of x, you can then review linear equations( imo, a big content of algebra). Stuff like slope, different linear forms, graphs of linear equations, and mostly linear equation word problems
- Then you can review system of equations. since you know how to manipulate linear equations, etc.
Then move on to other algebra topics dealing with algebra like
- functions, and different types of them
- exponents, and radicals rules
- inequalities.
- sequences.
- These aren't the heart of algebra but study them they are useful and it important to know them.
Since you learned different function rules, we can move on to learning exponetial functions, graphs, and word problems.
Then finally, learn most hard thing in Algebra: Quadratics.
Pratice,practice, and practice and you will pass.
Try to memorize the formulas and know when to apply it.
Good Luck
Answer: The original price was $6,400
Step-by-step explanation: To find the original price, divide the sale price by 1 minus the discount rate: 4160 / (1- 0.35) = 4160 / 0.65 = 6400
mark brainliest?? plz :)