Answer:
A. 31
Explanation:
The answer is A because a polynomial has at least two integers(more than two numbers) and A is just one integer, someone could get confused thinking is C but its not because <em>y³ </em>means <em>y×y×y, so that would not be the answer. </em>
Answer:
y-(-4)=-6(x-1)
its is either (x-1), or (x+1). Im not sure on the last part
Step-by-step explanation:
hope this helps :3
if it did pls mark brainliest
Perimeter of rectangle = length + length + width + width
To find the combinations, think of two numbers that each multiplied by 2 and added up to give 12 or 14
Rectangle with perimeter 12
Say we take length = 2 and width = 3
Multiply the length by 2 = 2 × 2 = 4
Multiply the width by 3 = 2 × 3 = 6
Then add the answers = 4 + 6 = 10
This doesn't give us perimeter of 12 so we can't have the combination of length = 2 and width = 3
Take length = 4 and width = 2
Perimeter = 4+4+2+2 = 12
This is the first combination we can have
Take length = 5 and width = 1
Perimeter = 5+5+1+1 = 12
This is the second combination we can have
The question doesn't specify whether or not we are limited to use only integers, but if it is, we can only have two combinations of length and width that give perimeter of 12
length = 4 and width = 2
length = 5 and width = 1
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Rectangle with perimeter of 14
Length = 4 and width = 3
Perimeter = 4+4+3+3 = 14
Length = 5 and width = 2
Perimeter = 5+5+2+2 = 14
Length = 6 and width = 1
Perimeter = 6+6+1+1 = 14
We can have 3 different combinations of length and width
Answer:
No I do not agree with Andre says that 3 divided by 2/3 Solving for 3 ÷ 2/3
3 ÷ 2/3
= 3 × 3/2
= 9/2
= 4 1/2
Therefore, 3 divided by 2/3 is 4 1/2
Andre's reasoning is wrong.
Step-by-step explanation:
It is incorrect
Let's divide and compare the sum
3 : 2/3 = 3*3/2 = 9/2 = 4 1/2
and
There are four 2/3 fractions and one 1/3 fraction
The 1/3 fraction is 1/2 of 2/3 fraction so instead of counting 1/3 as 1/3 it should be counted as 1/2