Answer:
At 6 pm, the temperature was 13°C below the freezing point
Step-by-step explanation:
Let us first express the information clearly to determine the temperature at 6 p.m:
The temperature in the morning = 6°C
the temperature at noon (12pm) = -13°C
It stayed at that temperature for six hours; this means that the temperature from 12 noon to 6 pm = -13°C
∴ Temperature at 6 pm = -13°C
Next let us calculate how far -13 is, below freezing point (0)
Difference = 0 - (-13)
= 0 + 13 = 13°C
Therefore, at 6 pm, the temperature was 13°C below the freezing point
Answer:
-206675344746
Step-by-step explanation:
1000*0+321*15678*9(-4563) = -206675344746
Answer:
a) 
, b) 
, for all 
Step-by-step explanation:
a) The slope associated with the mean value is:
Let differentiate the function:
The value associated with the slope is:
b) The slope associated with the mean value is:
Let differentiate the function:
The value associated with the slope is:
, for all
, for all
Answer:
Hey there!
3x-9=114
3x=123
x=41
Let me know if this helps :)
