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nexus9112 [7]
3 years ago
14

**30 POINTS**

Mathematics
1 answer:
leonid [27]3 years ago
7 0

Answer:....

What?

Step-by-step explanation:

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Simplify. Assume that no denominator is equal to zero. ([3^2]^3g^3h^4)^2
mariarad [96]

Answer:

531,441·g^6·h^8

Step-by-step explanation:

The operative rule of exponents is ...

(a^b)^c = a^(b·c)

Working from the inside out, according to the order of operations, we get ...

= (9^3·g^3·h^4)^2

= 729^2·g^(3·2)·h^(4·2)

= 531,441·g^6·h^8

7 0
3 years ago
The inequality of the graph
fiasKO [112]

Answer:

\displaystyle y > 4x - 2

Step-by-step explanation:

Starting from the y-intercept of \displaystyle [0, -2],you do \displaystyle \frac{rise}{run}by either moving four blocks <em>south</em><em> </em>over one block <em>west</em><em> </em>or four blocks <em>north</em><em> </em>over one block<em> east</em><em> </em>[<em>west</em> and <em>south</em> are negatives]. Next, we have to determine the types of inequality symbols that are suitable for this graph, which will be <em>less</em><em> </em><em>than</em><em> </em>and <em>greater</em><em> </em><em>than</em><em> </em>since this is a <em>dashed</em><em> </em><em>line</em><em> </em>graph. We then use the zero-interval test [test point (0, 0)] to ensure whether we shade the opposite portion [portion that does not contain the origin] or the portion that DOES contain the origin. At this step, we must verify the inequalities as false or true:

<em>Greater</em><em> </em><em>than</em>

\displaystyle 0 > 4[0] - 2 → 0 > -2☑

<em>Less</em><em> </em><em>than</em><em> </em>

\displaystyle 0 < 4[0] - 2 → 0 ≮ -2

This graph is shaded in the portion of the origin, so you would choose the <em>greater</em><em> </em><em>than</em><em> </em>inequality symbol to get this inequality:

\displaystyle y > 4x - 2

I am joyous to assist you anytime.

3 0
3 years ago
X=-3 which is a positive value? A x B x^2 C x^3 D x+3​
Gemiola [76]

Answer:

B. X squared is -3 times -3, which is equal to 9.

Step-by-step explanation:

5 0
3 years ago
PLSSS HELP ME!!!!!!!!!!! I WILL MARK U!!!!!
max2010maxim [7]

Answer:

a2

Step-by-step explanation:

you're using the pythagorean theorem

8 0
3 years ago
If f(1) = 0, what are all the roots of the function f(x)=x^3+3x^2-x-3? Use the Remainder Theorem.
Sophie [7]
There's no if about it, 

f(x)=x^3+3x^2-x-3&#10;

has a zero f(1)=0 so x-1 is a factor.   That's the special case of the Remainder Theorem; since f(1)=0 we'll get a remainder of zero when we divide f(x) by x-1.

At this point we can just divide or we can try more little numbers in the function.  It doesn't take too long to discover f(-1)=0 too, so  x+1 is a factor too by the remainder theorem.  I can find the third zero as well; but let's say that's out of range for most folks.

So far we have 

x^3+3x^2-x-3 = (x-1)(x+1)(x-r)

where r is the zero we haven't guessed yet.  Again we could divide f(x) by (x-1)(x+1)=x^2-1 but just looking at the constant term we must have

-3 = -1 (1)(-r) = r

so

x^3+3x^2-x-3 = (x-1)(x+1)(x+3)

We check f(-3)=(-3)^3+3(-3)^2 -(-3)-3 = 0 \quad\checkmark

We usually talk about the zeros of a function and the roots of an equation; here we have a function f(x) whose zeros are

x=1, x=-1, x=-3

8 0
2 years ago
Read 2 more answers
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