Answer:
531,441·g^6·h^8
Step-by-step explanation:
The operative rule of exponents is ...
(a^b)^c = a^(b·c)
Working from the inside out, according to the order of operations, we get ...
= (9^3·g^3·h^4)^2
= 729^2·g^(3·2)·h^(4·2)
= 531,441·g^6·h^8
Answer:

Step-by-step explanation:
Starting from the y-intercept of
you do
by either moving four blocks <em>south</em><em> </em>over one block <em>west</em><em> </em>or four blocks <em>north</em><em> </em>over one block<em> east</em><em> </em>[<em>west</em> and <em>south</em> are negatives]. Next, we have to determine the types of inequality symbols that are suitable for this graph, which will be <em>less</em><em> </em><em>than</em><em> </em>and <em>greater</em><em> </em><em>than</em><em> </em>since this is a <em>dashed</em><em> </em><em>line</em><em> </em>graph. We then use the zero-interval test [test point (0, 0)] to ensure whether we shade the opposite portion [portion that does not contain the origin] or the portion that DOES contain the origin. At this step, we must verify the inequalities as false or true:
<em>Greater</em><em> </em><em>than</em>
☑
<em>Less</em><em> </em><em>than</em><em> </em>
![\displaystyle 0 < 4[0] - 2 → 0 ≮ -2](https://tex.z-dn.net/?f=%5Cdisplaystyle%200%20%3C%204%5B0%5D%20-%202%20%E2%86%92%200%20%E2%89%AE%20-2)
This graph is shaded in the portion of the origin, so you would choose the <em>greater</em><em> </em><em>than</em><em> </em>inequality symbol to get this inequality:

I am joyous to assist you anytime.
Answer:
B. X squared is -3 times -3, which is equal to 9.
Step-by-step explanation:
Answer:
a2
Step-by-step explanation:
you're using the pythagorean theorem
There's no if about it,

has a zero

so

is a factor. That's the special case of the Remainder Theorem; since

we'll get a remainder of zero when we divide

by

At this point we can just divide or we can try more little numbers in the function. It doesn't take too long to discover

too, so

is a factor too by the remainder theorem. I can find the third zero as well; but let's say that's out of range for most folks.
So far we have

where

is the zero we haven't guessed yet. Again we could divide

by

but just looking at the constant term we must have

so

We check

We usually talk about the zeros of a function and the roots of an equation; here we have a function

whose zeros are