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Alexxx [7]
3 years ago
10

Which expressions are equivalent to 2 ( 4 f + 2 g ) Choose 3 answers

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
4 0

Answer:

Since there are no choices to choose from, I'll make it up.

8f + 4g

8(f + 1/2g)

4(2f + g)

Hope this helps!! Please mark as brainliest if you don't mind! Thanks ^^

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F ( x ) = 5^x+ 2; g ( x ) = 5^-x + 6
Anton [14]
*GUARANTEED ANSWER ✅*

Down below is the equation graphed

3 0
3 years ago
I don't think i've been so confused ever, how do I solve this using long division?
tankabanditka [31]

Check the picture below.

7 0
4 years ago
Use the net as an aid to compute the surface area (rounded to the nearest integer) of the triangular pyramid with an equilateral
aleksandrvk [35]

Answer:

Correct answer is C)\ 254\ m^{2}

Step-by-step explanation:

As per the given diagram, we know the following details:

Height of the triangular pyramid is <em>14m</em>.

<em>Side of base</em> = <em>10m </em>

Height of Triangular base = <em>8.7m</em>

Formula for <em>surface area of triangular pyramid</em>:

\text{Area = Area of Triangular base + 3 }\times\text{Area of side triangle}

(Triangular base is shown in the dotted lines in the question figure.

The other 3 triangles are the side triangles.)

We know that,

\text{Area of a triangle = }\dfrac{1}{2} \times \text{Base} \times \text{Height}

\Rightarrow \text{Required Surface Area = } \dfrac{1}{2} \times 8.7 \times 10 + 3 \times \dfrac{1}{2} \times 14 \times 10\\\Rightarrow \dfrac{1}{2}\times (87 + 3 \times 140)\\\Rightarrow \dfrac{1}{2}\times (87 + 420)\\\Rightarrow \dfrac{1}{2} \times 507\\$\approx$ 254 m^{2}

Hence correct answer is C)\ 254\ m^{2}.

3 0
3 years ago
Help if right U GET ................. U KNO WAH
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Answer:

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Step-by-step explanation:

6 0
3 years ago
Please help! I attached the question below.
kompoz [17]

Answer:

\frac{2(c+2)}{c(c-2)}

Step-by-step explanation:

\frac{c^{2}-4 }{6c^{4}+15c^{3}}=\frac{(c-2)(c+2)}{c(6c^{3}+15c^{2}) }

Identity used:

a^{2}-b^{2}=(a-b)(a+b)

\frac{c^{2}-4c+4}{12c^{3}+30c^{2}}=\frac{(c-2)^{2}}{2(6c^{3}+15c^{2}) }

Now let us divide the modified expressions:

\frac{(c-2)(c+2)}{c(6c^{3}+15c^{2})} ÷ \frac{(c-2)^2}{2(6c^{3}+15c^{2}) }

we get:

\frac{2(c+2)}{c(c-2)}

5 0
4 years ago
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