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Misha Larkins [42]
3 years ago
9

Write an equation for a sine function and for a cosine function.

Mathematics
1 answer:
ki77a [65]3 years ago
6 0

Answer: 1/2

Step-by-step explanation:

f(x) = A sin (Bx - C) + D

amplitude = |A|

period =

phase shift =

vertical shift = D

A

amplitude of 3 is given so  3 = |A| → A = ± 3, since it is stated that this is a positive function, then A = 3

B

period of 6π is given so

C

D

vertical shift of -1 is given so -1 = D

Now, substitute the values of A, B, C, and D into the formula (above):

Next, solve when x = 2π

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Can u help me on number 9 plz thank u
stepladder [879]

Answer:

the differenc is 123 degrees

Step-by-step explanation:

97 + 26 = 123

3 0
4 years ago
Hi guys, I need help on this practice anyone willing to help; list of things to do
andreyandreev [35.5K]

Answer:

B. y = x - 2

Step-by-step explanation:

The sale price (y) is $2 less than the original price (x - 2).

To test this out, if a book's original price is $10..

x = 10

Using y = x - 2 and to test out if it works, we'll plug in x = 10 to discover y.

y = 10 - 2

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5 0
3 years ago
Compare the fraction 3/5 to 1/2 and then compare 2/6 to 1/2 .use symbols in your answer.
Feliz [49]
3/5 > 1/2 ~ because 3/5 is 60% of 1 and 1/2 is 50% of 1 
2/6<1/2 ~ because 2/6 is 33% of 1 and 1/2 is 50% of 1

Hope I helped!
~ Zoe
3 0
4 years ago
Evaluate the function at the indicated values. (If an answer is undefined, enter UNDEFINED.) f(x) = 8x + 9 f(1) = f(−2) = f 1 2
creativ13 [48]

Answer:

f(1)=17

f(-2)=-7

f(\frac{1}{2})=13

Step-by-step explanation:

We are given that a function f(x)=8x+9

We have to evaluate f(1),f(-2) and f(\frac{1}{2})

Substitute x=1 in the given function  then we get

f(1)=8(1)+9=17

f(1)=17

Substitute x=-2 in the given function then we get

f(-2)=8(-2)+9=-16+9=-7

f(-2)=-7

Substitute x=\frac{1}{2}

Then we get

f(\frac{1}{2})=8(\frac{1}{2})+9=4+9=13

f(\frac{1}{2})=13

7 0
3 years ago
Suppose that you construct a 95% confidence interval for the population mean, using some sample values, and you obtain the range
mel-nik [20]

Answer:

Step-by-step explanation:

Hello!

You have the 95% CI for the mean [50; 70]

The amplitude for this interval is a= 20 and its margin of error is d= 10.

If the interval was constructed as X[bar] ± margin of error

Where the margin of error is the product of the statistic value due to the standard deviation of the distribution.

If you reduce the confidence level, the value of the statistic will be also reduced, so you would expect a shorter margin of error and amplitude for the 90% CI

Symbolically: d= Z_{1-\alpha/2} * (δ/√n) ⇒ d↓= Z_{1-\alpha/2}↓ * (δ/√n) if d↓ ⇒ a↓

50 to 100 has an a= 50 and d= 25

70 to 90 has an a= 20 and d= 10

60 to 80 has an a= 20 and d= 10

55 to 95 has an a= 40 and d= 20

65 to 85 has an a=20 and d= 10

None of the given intervals corresponds to a 90% interval for the same sample as the first interval 50 to 70.

Another detail to keep in mind is that the intervals for the population mean are centered in the sample mean. From the first interval you can deduce that it is centered in X[bar]= 60 (Upper bond - margin of error = sample mean), if the other intervals were constructed with the same sample values, they should all be centered in 60.

I hope you have a SUPER day!

7 0
4 years ago
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