Question

Evaluate the function at the indicated values. (If an answer is undefined, enter UNDEFINED.) f(x) = 8x + 9 f(1) = f(−2) = f 1 2 = f(a) = f(−a) = f(a + b) =

Answer 1

Answer:

f(1)=17

f(-2)=-7

$f(\frac{1}{2})=13$

Step-by-step explanation:

We are given that a function $f(x)=8x+9$

We have to evaluate f(1),f(-2) and $f(\frac{1}{2})$

Substitute x=1 in the given function  then we get

$f(1)=8(1)+9=17$

f(1)=17

Substitute x=-2 in the given function then we get

$f(-2)=8(-2)+9=-16+9=-7$

f(-2)=-7

Substitute $x=\frac{1}{2}$

Then we get

$f(\frac{1}{2})=8(\frac{1}{2})+9=4+9=13$

$f(\frac{1}{2})=13$