What are the domain and range of function w?

how do you solve this problem. there are approximately 2.1 million deaths per year in country A. Express this quantity as deaths

slamgirl [31]

Well... we know that... there are 365 days in a year, unless is a leap-year, but we'll use 365 anyway

and each day has 24hrs, each hr has 60 minutes

so. let us use those ratios

$\bf 2.1million\iff 2.1E6\iff 2,100,000\qquad thus
\\\\\\
\cfrac{2100000\ deaths}{1\ year}\cdot \cfrac{1\ year}{365\ day}\cdot \cfrac{1\ day}{24\ hr}\cdot \cfrac{1\ hr}{60\ minute}$

so.. multiply and simplify, cancelling out any like-units atop and bottom

notice, all we do, is use the ratios, in a way, that if we need one unit to be changed, we flip the ratio

for example, to toss away "year" unit, since in the first fraction is at the bottom, then we put it on the top on the ratio, year/year = 1, effectively cancelling the unit

5 0

4 years ago

Read 2 more answers

"You measure 34 dogs' weights, and find they have a mean weight of 67 ounces. Assume the population standard deviation is 13.5 o

liraira [26]

Answer:

The 95% confidence interval for the true population mean dog weight is between 62.46 ounces and 71.54 ounces.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.95}{2} = 0.025$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.025 = 0.975$ , so $z = 1.96$

Now, find M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

$M = 1.96*\frac{13.5}{\sqrt{34}} = 4.54$

The lower end of the interval is the sample mean subtracted by M. So it is 67 - 4.54 = 62.46 ounches.

The upper end of the interval is the sample mean added to M. So it is 67 + 4.54 = 71.54 ounces.

The 95% confidence interval for the true population mean dog weight is between 62.46 ounces and 71.54 ounces.

7 0

4 years ago

What is true of the type of angle in this lesson? It measures half the sum of the arc it intercepts. It measures twice the sum o

Karolina [17]

Answer:

Step-by-step explanation:

Answer: it is C because it is true of the type of angle in this lessonc. It measures half the difference of the arcs it intercepts.

7 0

3 years ago

RST is dilated with the rule DT,1/3 (x, y), where the center of dilation is T(3, –2). The distance between the x-coordinates of

steposvetlana [31]

Answer:the distance between the x coordinates of R and T is 3.

The distance between the y coordinates of R and T is 6

R’ is 1 unit left, 2 units up from T, so the coordinates of R’ are (2,0)

10 0

3 years ago

Read 2 more answers

calculates the sum of the first 8 terms of an arithmetic progression starting with 3/5 and ending with 1/4

N76 [4]

We conclude that the sum of the first 8 terms of the arithmetic sequence is 17/5.

<h3>How to get the sum of the first 8 terms?</h3>

In an arithmetic sequence, the difference between any two consecutive terms is a constant.

Here we know that:

$a_1 = 3/5\\a_8 = 1/4$

There are 7 times the common difference between these two values, so if d is the common difference:

$a_1 + 7*d = a_8\\\\3/5 + 7*d = 1/4\\\\7*d = 1/4 - 3/5 = (5 - 12)/20 = -7/20\\\\d = -1/20$

Then the sum of the first 8 terms is given by:

$3/5 + (3/5 - 1/20) + (3/5 - 2/20) + ... + (3/5 - 7/20)\\\\8*(3/5) - (1/20)*(1 + 2 + 3+ 4 + 5 + 6 + 7) = 3.4 = 34/10 = 17/5$

So we conclude that the sum of the first 8 terms of the arithmetic sequence is 17/5.

If you want to learn more about arithmetic sequences:

brainly.com/question/6561461

#SPJ1

6 0

2 years ago