Answer:
$29.25
Step-by-step explanation:
39 x .25 = 9.75
39 - 9.75 = 29.25
Answer:
1)-
How to solve your question
Your question is
4(4−72)−9(5+2)
4(4y-7y^{2})-9(5y+2)4(4y−7y2)−9(5y+2)
Simplify
1
Rearrange terms
4(4−72)−9(5+2)
4({\color{#c92786}{4y-7y^{2}}})-9(5y+2)4(4y−7y2)−9(5y+2)
4(−72+4)−9(5+2)
4({\color{#c92786}{-7y^{2}+4y}})-9(5y+2)4(−7y2+4y)−9(5y+2)
2
Distribute
4(−72+4)−9(5+2)
{\color{#c92786}{4(-7y^{2}+4y)}}-9(5y+2)4(−7y2+4y)−9(5y+2)
−282+16−9(5+2)
{\color{#c92786}{-28y^{2}+16y}}-9(5y+2)−28y2+16y−9(5y+2)
3
Distribute
−282+16−9(5+2)
-28y^{2}+16y{\color{#c92786}{-9(5y+2)}}−28y2+16y−9(5y+2)
−282+16−45−18
-28y^{2}+16y{\color{#c92786}{-45y-18}}−28y2+16y−45y−18
4
Combine like terms
2)
−17y+17z+24
See steps
Step by Step Solution:

STEP1:Equation at the end of step 1
((24 - 4 • (5y - 6z)) + 3y) - 7z
STEP2:
Final result :
-17y + 17z + 24
−282+16−45−18
-28y^{2}+{\color{#c92786}{16y}}{\color{#c92786}{-45y}}-18−28y2+16y−45y−18
−282−29−18
-28y^{2}{\color{#c92786}{-29y}}-18−28y2−29y−18
Solution
−282−29−18
Is this the whole question?
Answer:
97.7% of of the boxes weigh more than 22.9 ounces.
15.9% of of the boxes weigh less than 23.7 ounces.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 24.5 ounces
Standard Deviation, σ = 0.8 ounce
We are given that the distribution of boxes weight is a bell shaped distribution that is a normal distribution.
Formula:
a) P(boxes weigh more than 22.9 ounces)
P(x > 22.9)
Calculation the value from standard normal z table, we have,
97.7% of of the boxes weigh more than 22.9 ounces.
b) P(boxes weigh less than 23.7 ounces)
P(x < 23.7)
Calculation the value from standard normal z table, we have,
15.9% of of the boxes weigh less than 23.7 ounces.
Answer:
29/5 =x
Step-by-step explanation:
25 = 5x − 4
Add 4 to each side
25+4 = 5x − 4+4
29 = 5x
Divide each side by 5
29/5 = 5x/5
29/5 =x
