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Amanda [17]
3 years ago
8

A circular rug has a circumference of 314 inches. What is the approximate area? Round to the nearest whole inch. Use 3.14 for pi

e 
Mathematics
2 answers:
lana66690 [7]3 years ago
8 0

Answer:

7,850

Step-by-step explanation:

Semenov [28]3 years ago
6 0

Answer:

The area is 7850 square inches

Step-by-step explanation:

Given the circumference, we want to calculate the area

mathematically, the circumference is;

C = 2 pi r

So r is C/2 pi

Area = pi * r^2

Substitute value for r from circumference;

Area = Pi * c^2/4pi^2

Area = C^2/4pi

Area = 314^2/4 * 3.14

Area = 7850 Inches square

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(6+3)-+8-7)=<br>(1+4)+(10-8)=<br>(3-3+(9+1)=<br>(10-2)+(10-8)=<br>2+(0+1+2+3)=<br>(10-1-2-3)+4=​
JulijaS [17]

Answer:

6+3-8-7 = 8

1+4+10-8 = 7

3-3+9+1 = 10

10-2+10-8 = 10

2+0+1+2+3 = 8

10-1-2-3+4 = 8

Step-by-step explanation:

i don't know if these are supposed to be easy or not lol but thanks for the points :p

6 0
2 years ago
8a + 12b = 92 6a – 4b = 4 -- a =? b = ?
Yanka [14]

Answer:

a = 4 b = 5

Step-by-step explanation:

8a + 12b = 92......eqn 1

6a - 4b = 4......eqn 2

multiply eqn 2 by 3

18a - 12b = 12.....eqn 2

add eqn 1 and 2 to eliminate b

26a = 104

a = 4

put a = 4 into eqn 2

18(4) - 12b = 12

72 - 12b = 12

72 - 12 = 12b

60 = 12b

5 = b

6 0
2 years ago
Find the H.C.F of the following expressions.
MAVERICK [17]

Step-by-step explanation:

Hey there!

Please look your required answer in pictures.

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6 0
2 years ago
a bathtub that hols 32 gallons of water contains 12 gallons of water you begin filling it and after 5 minutes the tub is full
kramer
Okay. I am guessing that you are asking for the amount of water poured per minute. The bathtub already holds 12 gallons and 32 - 12 is 20. The tub is full in 5 minutes. Let’s divide. 20/5 is 4. There are 4 gallons of water filled in the tub per minute.
7 0
3 years ago
Do the functions have the same concavity?
Vesna [10]

Answer:

Step-by-step explanation:

Function f is graphed. The positive x-axis contains point c. The graph consists of an N-shaped curve. The curve starts in quadrant 3, moves upward concave down to a point in quadrant 1, moves downward concave down to point c in quadrant 1, continues downward concave up to a point in quadrant 4, moves upward concave up and ends in quadrant 1. The curve is purple to the left of point c, where it is concave down, and is green to the right of point c, where it is concave up.

Notice how fff is \purpleC{\text{concave down}}concave downstart color #aa87ff, start text, c, o, n, c, a, v, e, space, d, o, w, n, end text, end color #aa87ff to the left of x=cx=cx, equals, c and \greenD{\text{concave up}}concave upstart color #1fab54, start text, c, o, n, c, a, v, e, space, u, p, end text, end color #1fab54 to the right of x=cx=cx, equals, c.

PROBLEM 1

Let fff be a twice differentiable function. This is the graph of its second derivative, f''f  

′′

f, start superscript, prime, prime, end superscript.

Function f double prime is graphed. The x-axis goes from negative 8 to 8. The graph consists of a wave-shaped curve. The curve starts at (negative 8, 0), moves downward concave up to (negative 5, negative 5), moves upward concave up to (negative 2, 0), continues upward concave down t

 

 

 

 

 

 

7 0
3 years ago
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