First you plug in the missing values
5(8×5/8+3×3-5×2) = 20
Answer:
<u>Apply the property above:</u>
- 1. ln 618 = p ⇔ e^p = 618
- 2. ln q = 2 ⇔ e^2 = q
- 3. ln 100 = t ⇔ e^t = 100
- 4. ln (e^3) = 3 ⇔ e^3 = e^3
Given:
Area of a circle, A=50.265 sq. units.
Radius of circle, r = 4 units.
To find:
The value of π to the nearest thousandth.
Solution:
Formula for area of a circle is



Now, using
expression, we can find the value of π.




Approximate the value to the nearest thousandth (three digits after decimal).

Therefore, the approximated value of π is 3.142.
Answer:
If A = 8, B = 5
If A = 20, B = 3
Step-by-step explanation:
4x²(2x³ + 5x)
8x⁵ + 20x³
If A = 8, B = 5
If A = 20, B = 3
Answer:
x = 5/2,2
Step-by-step explanation: