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Deffense [45]
3 years ago
12

Pls try doing these 3 it is only one question each page

Mathematics
2 answers:
dusya [7]3 years ago
7 0

Answer:

yes

Step-by-step explanation:

MariettaO [177]3 years ago
7 0

Answer: 14x+11 ,8x−20,6x+12,1

Step-by-step explanation:

(4)(2x)+(4)(−1)+(3)(2x)+(3)(5)

=8x+−4+6x+15

Combine Like Terms:

=8x+−4+6x+15

=(8x+6x)+(−4+15)

=14x+11

(6)(2x)+(6)(−3)+(−2)(2x)+(−2)(1)

=12x+−18+−4x+−2

Combine Like Terms:

=12x+−18+−4x+−2

=(12x+−4x)+(−18+−2)

=8x+−20

(2)(5x)+(2)(3)+(−2)(2x)+(−2)(−3)

=10x+6+−4x+6

Combine Like Terms:

=10x+6+−4x+6

=(10x+−4x)+(6+6)

=6x+12

You might be interested in
Red Bookstore wants to ship books from its warehouses in Brooklyn and Queens to its stores, one on Long Island and one in Manhat
frozen [14]

Answer:

a)

Brooklyn to Long Island = 0 books

Brooklyn to Manhattan = 1000 books

Queens to Long Island books  = 1500 books

Queens to Manhattan books = 500 books

b)

YES

Step-by-step explanation:

This is a equation's system with 4 unknown variables ( the number of the 4 kinds of shippings performed) , lets call the 4 variables like this:

  • a: Brooklyn to Long Island books
  • b: Brooklyn to Manhattan books
  • c: Queens to Long Island books
  • d: Queens to Manhattan books

Now, let´s see what we know:

1) First we know that each bookstore has asked for 1500 books so:

  • 1500= b+d => b= 1500-d (1)
  • 1500= a+c=> a= 1500-c (2)

2) We also know that the total amount spent  in transportation is 9000$ at the given individual trasportattion prices

9000$= 5$*a+1$*b+4$*c+2$*d

=> 9000= 5a+b+4c+2d

=> c= (9000-5a-b-2d)/4 (3)

3) Finally, we know that the since we have a total number of books in the two warehouses of 3000 books, the same quantity that is demanded by the two bookstores, all the books are delivered.

So , in Brooklyn there are 1000 books that can be delivered to LI or Manhattan:

  • 1000 = a+b => a= 1000-b (4)

and in Queens there are 2000 books:

  • 2000 = c+d => d= 2000-c (5)

Now, formulas (2) and (4) are equal to a, so they are equal to each other

1000-b= 1500-c => b= c-500 (6)

Now lets solve by substitution in formula (3):

c= (9000-5a-b-2d)/4

=> 4c= 9000-5a-b-2d

=> 4c= 9000-5( 1500-c)- (c-500)-2*(2000-c)

=> 4c= -3000+6c =><em> c=1500</em>

Then:

  • d= 2000-c= 2000-1500=><em> d=500.</em>
  • b= c-500 => <em>b= 1000</em>
  • a=<em> </em>1500-c <em>=> c= 0</em>

b) If we look at the trsnportation prices the cheaper is from Brooklyn to Manhattan, so lets try to maximize this tranportation.

In Brooklyn we have 1000 books, and we need 1500  in Manhattan, so lets do all the the shipping from brooklyn to Manhattan.:

  • 1000 books *1 $/ book= 1000$

We will need 500 additional books from Queens at 2$/ book:

  • 500 books * 2 $/book = 1000$

Then the 1500 books left in Queens will be shipped to Long Island at a price of 4$/ book:

  • 1500 books * 4 $/book= 6000$

Total amount spent = 1000$+1000$+6000$ = 8000$

3 0
4 years ago
This one is extremely confusing I’ve worked it out 6 times and still no answer can somebody plz help
vivado [14]
It should be A
Angle b=angle g
6x+8=4x+12
2x=4
6 0
4 years ago
Read 2 more answers
The school sold 200 tickets to play. Student tickets are $4 and adult tickets are $6. If they made a total $930 how many of each
motikmotik

Answer:

65 adult tickets and 135 student tickets were sold.

Step-by-step explanation:

4s + 6a = 930

s + a = 200

s = -a + 200

4(-a + 200) + 6a = 930

-4a + 800 + 6a = 930

2a + 800 = 930

2a = 130

a = 65

There were 65 adult tickets sold.

200 - 65 = 135

There were 135 student tickets sold.

Check:

4(135) + 6(65) = 930

540 + 390 = 930

930 = 930

7 0
3 years ago
Please help thank you
OLga [1]

Answer:

6

∑  n^2

n=1

Step-by-step explanation:

There are 6 terms in the series, so we sum from 1 to 6

The terms are the integers squared

1^1, 2^2, 3^2 4^2, 5^2 6^2  or n^2

6

∑  n^2

n=1

7 0
3 years ago
Please help I need it done right now
Lina20 [59]

Use the way that kids use i.e trial and error method .

Solution:-

The set given by

\\ \rm\longmapsto \left\{32+n,\dfrac{n}{8},\sqrt{n+225}\right\}

Lets understand

  • See the first term any natural value will make it natural .

Come to 2nd one.

  • n should be a multiple of 8 to make it whole.

Come to third one

  • n should be a number which makes the sum a perfect square by which we get a natural no.We have to solve it w.r.t to 2nd one

Lets think

Nearest squares to 225 are 196 and 289

We can't take 196 as we have to take a positive one other wise it will come in terms of i.

Take 289

\\ \rm\longmapsto n+225=289

\\ \rm\longmapsto n=289-225=64

Its divisible by 8 .

Rewrite the set

\\ \rm\longmapsto \left\{64+32,\dfrac{64}{8},\sqrt{225+64}\right\}

\\ \rm\longmapsto \left\{96,8,\sqrt{289}\right\}

\\ \rm\longmapsto \left\{96,8,17\right\}

Hence n=64

8 0
3 years ago
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