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nikklg [1K]
3 years ago
13

Try To Solve It And If Right I give thanks and 5 star rate

Mathematics
1 answer:
valina [46]3 years ago
8 0
The answer is A or I
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Use the picture attached.
PIT_PIT [208]

Answer: the answer is choice b which is 0 .

Step-by-step explanation: Any irregular quadrilateral has zero lines of symmetry because the sides are not equal so they won't form equivalent sides . This shape or quadrilateral can't be divided to lines of symmetry as the sides won't be equal . HOPE IT HELPS YOU BUDDY .PLEASE GIVE BRAINLIEST .THANKS .

7 0
2 years ago
Read 2 more answers
A basket contains one giraffe (G), one panda (P), one monkey (M), and one teddy bear (T). Kelly randomly picks one toy from the
sasho [114]
See the attached picture for the answer:

5 0
3 years ago
Read 2 more answers
Given the following polynomial find the maximum possible number of turning points. f(x)=x^11+x^10+x^12+x^9
11111nata11111 [884]
Turning points are inflection points

think
1st degree (linear) has no turning/inflecion points
2nd degree (quadratic, parabola) has  1 turning/inflection point
so
nth degree has n-1 turning/inflection point

this is 11th degree since highest power is 12
12-1=11
11 turning oints
5 0
3 years ago
Carrie wished to build a rectangular dog run along theside of her garage. The garage will serve as one side of the fence. If she
Nat2105 [25]

Given:

Carrie has 180 ft of the fencing and wishes the fence to be 4times as long as it is wide.

To Find:

The area in square feet that the fencing encloses.

Answer:

The fence encloses 3600 sq ft.

Step-by-step explanation:

Let x denote the length of the dog run and y denote the width of the dog run.

Given that the garage wall serves as one side of the dog run, we are left with 3 other sides to instal the fence.

Carrie has 180ft of fencing with her, so the sum of the lengths of the 3 sides has to be equal to 180. We can represent this in the form of an equation as

x+y+y=180\\\\x+2y=180\\\\x=180-2y

We are also given that Carrie wishes the fence to be 4 times as long as it is wide.

So,

x=4y

Replacing this value into the first equation, we have

4y=180-2y\\\\
6y=180\\\\
y=30

Therefore,

x=(4)(30)=120

Thus, the length of the dog run is 120ft and the width is 30ft.

The area enclosed will be equal to the length multiplied with the width. So,

(120)(30)=3600

The fence encloses 3600 sq ft.


4 0
3 years ago
15% of R560 - 15% of R500 is:​
Dahasolnce [82]

15% of R560 - 15% of R500

=> 0.15 × 560 – 0.15 × 500

=> 0.15 ( 560–500)

=> 0.15 × 60

=> Rs. 9

HOPE IT HELPS

PLEASE MARK ME BRAINLIEST ☺️

8 0
3 years ago
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