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1 year ago

A boat is heading towards a lighthouse, whose beacon-light is 136 feet above the

1 answer:

alexandr1967 [171]1 year ago

5 0

The distance between the points A to B is 899.9 feet. After rounding off the nearest integer we get 900 feet as the final answer.

Given we know that CD is perpendicular to AD.

The distance between CD is 139 feet.

As from points A the boat's crew measure the angle of elevation to the beacon as 6°

therefore, m∠A = 6°

Another time the angle of elevation is measured from point B which is 19°.

therefore, m∠DBC = 19°

tan 19° = CD/BD

BD = CD/tan19°

BD = 136/tan 19°

now for tan 6° = CD/AD (tangent is opposite over adjacent)

AD = CD/tan 6°

AD = 136/tan 6°

AB = AD ₋ BD

AB = 136/tan 6° ₋ 136/tan 19°

AB = 1295.2 ₋ 395.3

AB = 900 feet

hence the distance from point A to B is 900 feet.

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2 years ago

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1 year ago

The random variable X~(30,2^2) Find p(X<33) Find p(X>26)

Ostrovityanka [42]

Answer:

i) P(X<33) = 0.9232

ii) P(X>26) = 0.001

Step-by-step explanation:

Step(i):-

Given that the mean of the Population = 30

Given that the standard deviation of the Population = 4

Let 'X' be the Normal distribution

Step(ii):-

Given that the random variable X = 33

$Z = \frac{x-mean}{S.D}$

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P(X<33) = P( Z<1.5)

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= 1 - ( 0.5 - A(1.5))

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Step(iii) :-

Given that the random variable X = 26

$Z = \frac{x-mean}{S.D}$

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P(X>26) = P( Z>3.5)

= 0.5 - A(3.5)

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2 years ago