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Leviafan [203]
3 years ago
11

What are 2 numbers that add to 16 and multiply to 10

Mathematics
1 answer:
harkovskaia [24]3 years ago
8 0
Find multipules of 10
1 and 10
2 and 5
1+10=11 NO
2+5=7 ono

so do
x+y=16
xy=10

x+y=16
subtract x from both sides
y=16-x
subsitute
x(16-x)=10
distribute
16x-x^2=10
add x^2 to btoh sides
16x=x^2+10
subtrac 16 x from oth sies
0=x^2-16x+10
use quadratic formula which is
x=\frac{-b+/- \sqrt{ b^{2}-4ac } }{2a} when you have
0=ax^2+bx+c

0=x^2-16+10
a=1
b=-16
c=10
subsitute
x=\frac{-(-16)+/- \sqrt{ (-16)^{2}-4(1)(10) } }{2(1)}
x=\frac{16+/- \sqrt{ 256-40 } }{2}
x=\frac{16+/- \sqrt{ 216 } }{2}
x=\frac{16+/- 6\sqrt{6 } }{2}
x=8+/- 3\sqrt{6}
x=8+3 \sqrt{6} or 8-3 \sqrt{6}
aprox
x=15.3485 or 0.651531
so thos are the 2 numbers


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y = (1/3)x +5/3

Step-by-step explanation:

The general equation of a line is

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The doubling period of a bacteria population is 10 minutes. At time t = 110 minutes, the bacterial population was 800.
goldenfox [79]

The initial population at time t = 0 was 0.39 while the size of the bacteria population after 4 hours was 6553600

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

Let y represent the bacteria population at time t. a represent the initial population at t = 0. Since the doubling period of a bacteria population is 10 minutes, hence:

y=a(2)^\frac{t}{10}

At time t = 110 minutes, the bacterial population was 800. Hence:

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At 4 hours (240 minutes):

y=0.39(2)^\frac{240}{10} =6553600

The initial population at time t = 0 was 0.39 while the size of the bacteria population after 4 hours was 6553600

Find out more on equation at: brainly.com/question/2972832

#SPJ1

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