All categories

2 years ago

-1/3x<48 solve this inequality

1 answer:

4 0

-1/3x < 48

Divide each side by -1/3. When you divide by a negative the sign flips...

x > 48 ÷ -1/3

divide fractions by multiplying the reciprocal of the divisor

x > 48 × -3
x > -144

You might be interested in

Give 2 numbers that fit this description: a number is less than another number but has a greater absolute value. Describe how yo

krek1111 [17]

X<y
|x|>y
This is fairly simple. X is obviously a negative number, and can be as well, though the value of y isn't terribly important so long as it is a larger number than x.

It could be x= -91, y=-90, or it could be x= -2, y=3, as two examples.

The absolute value sign stipulation is a clue that the contents are probably a negative number

4 0

3 years ago

Which ordered pair is not a point of the graph of y=1/2x-7

Tresset [83]

Where is the graph???

4 0

2 years ago

A contractor is building a fence around a square garden that has a side length of 3 inches in a

Pavel [41]

Answer:

is it adding or subtraction

7 0

1 year ago

Need help!

Maslowich

Answer: Choice D) |K| = 57

------------------------------------------------------

Explanation:

The notation |K| means "the number of items in set K". It is similar to the notation n(K). In this case, we simply add up all the values in the circle labeled K. There are four of these values which are 13, 8, 17, 19. Add up these values to get 13+8+17+19 = 57. So there are 57 items in set K.

4 0

3 years ago

According to the February 2008 Federal Trade Commission report on consumer fraud and identity theft, 23% of all complaints in 20

Murljashka [212]

Answer:

There is not enough evidence to support the claim that Alaska had a lower proportion of identity theft than 23%.

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 1432

p = 23% = 0.23

Alpha, α = 0.05

Number of theft complaints , x = 321

First, we design the null and the alternate hypothesis

$H_{0}: p = 0.23\\H_A: p < 0.23$

This is a one-tailed test.

Formula:

$\hat{p} = \dfrac{x}{n} = \dfrac{321}{1432} =0.2241$

$z = \dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}$

Putting the values, we get,

$z = \displaystyle\frac{0.2241-0.23}{\sqrt{\frac{0.23(1-0.23)}{1432}}} = -0.5305$

Now, we calculate the p-value from the table.

P-value = 0.298

Since the p-value is greater than the significance level, we fail to reject the null hypothesis and accept the null hypothesis.

Conclusion:

Thus, there is not enough evidence to support the claim that Alaska had a lower proportion of identity theft than 23%.

5 0

2 years ago