Answer:
The problem simplified is
Step-by-step explanation:
Exact form: -139/24
Decimal form: -5.791666....
mixed number form: -5 19/24
i hope this really helps
Answer:
6.56 g
Step-by-step explanation:
We can write the mass of radioactive isotope left after a time t by using the equation
where
is the initial amount of radioactive isotope
is the half-life
is the time
In this problem, we want to know the amount of radioactive isotope left after 5 half-lives, so after
Substituting into the equation, we have
The domain for the function is [10,∞) {x|x≥10}
Answer:
1
Step-by-step explanation:
( 50 / 5² )² ÷ 4 (by PEDMAS, do the terms inside the parentheses first)
= [ (5 · 10) / (5 · 5) ]² ÷ 4 (the 5's cancel out in the numerator and denominator)
= [ (10) / (5) ]² ÷ 4
= [ 2 ] ² ÷ 4
= 4 ÷ 4
= 1
Hope this helps
Answer:
Step-by-step explanation:
A) Let x represent minutes used, and C represent monthly charge. We are given two (x, C) pairs: (370, 133.00) and (530, 181.00)
We can use these in the 2-point form of the equation for a line.
y = (y2 -y1)/(x2 -x1)(x -x1) +y1
C = (181 -133)/(530 -370)(x -370) +133
C = 48/160(x -370) +133
C = 0.30x -111 +133
C = 0.30x +22
__
B) For x = 477 minutes, the charge will be ...
C = 0.30(477) +22 = $165.10 . . . . for 477 minutes
