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Answer:
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Class 9
>>Maths
>>Quadrilaterals
>>Quadrilaterals and Their Various Types
>>In Fig. 6.43, if PQ PS, PQ∥ SR, SQR = 2
Question
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In Fig. 6.43, if PQ⊥PS,PQ∥SR,∠SQR=28
0
and ∠QRT=65
0
, then find the values of x and y.
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Medium
Solution
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Given, PQ⊥PS,PQ∥SR,∠SQR=28
∘
,∠QRT=65
∘
According to the question,
x+∠SQR=∠QRT (Alternate angles as QR is transversal.)
⇒x+28
∘
=65
∘
⇒x=37
∘
Also ∠QSR=x
⇒∠QSR=37
∘
Also ∠QRS+∠QRT=180
∘
(Linear pair)
⇒∠QRS+65
∘
=180
∘
⇒∠QRS=115
∘
Now, ∠P+∠Q+∠R+∠S=360
∘
(Sum of the angles in a quadrilateral.)
⇒90
∘
+65
∘
+115
∘
+∠S=360
∘
⇒270
∘
+y+∠QSR=360
∘
⇒270
∘
+y+37
∘
=360
∘
⇒307
∘
+y=360
∘
⇒y=53
∘
Step-by-step explanation:
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<h2>Domain:</h2><h2>- ∞ < x < ∞</h2>
<h2>Range:</h2><h2>y≤9</h2>
Answer:
603
Step-by-step explanation:
The rate of change is found by
rate of change = f(b) -f(a)
------------
b-a
We need to find the rate of change for the interval 7,9 and 4,6
We know b= 9 and a = 7
f(9) -f(7)
------------
9-7
3878-1852
----------------
9-7
2026
-------
2
1013
We know b= 6 and a = 4
f(6) -f(4)
------------
6-4
1178-358
---------------
6-4
820
------
2
410
It asks how much greater, that means subtraction
1013-410
603
