The radius of the base of the vase in cm to 2 dp is 0.08m
<h3>Pressure of an object</h3>
The formula for calculating the pressure of a object is expressed as;
Pressure = Force/Area
Area = Force/Pressure
Area = 15/750
Areas = 0.02m²
Since the area of the circular base is πr², then;
πr² = 0.02
r² = 0.02/3.14
r = 0.0798m
Hence the radius of the base of the vase in cm to 2 dp is 0.08m
Learn more on pressure here; brainly.com/question/25736513
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Answer:
1
Step-by-step explanation:
Answer:
The answer of 5 ⅔ ÷ 4 ⅔= 1 3/14
I'm afraid your equation is not correctly set up. You need to identify the longest side of this right triangle; it is x. This is the "hypotenuse." Next, identify the lengths of the legs: they are sqrt(13) and 2sqrt(2).
Here's a refresher on the Pythagorean Theorem:
(hypotenuse)^2 = (leg 1)^2 + (leg 2)^2
Applying this Theorem here, [x]^2 = [2sqrt(2)]^2 + [sqrt(13)\^2
Solve this for x^2, and then take the positive root (only) of your result.