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stealth61 [152]
3 years ago
9

What's the answer? Plz explain

Mathematics
1 answer:
alukav5142 [94]3 years ago
4 0

she drove f + g miles total, and she covered m miles one way and m miles the other way, so she covered 2m miles, bundling them up it for miles per hour, it should give us

\bf \cfrac{\stackrel{total~miles}{2m}}{\stackrel{total~hours}{f+g}}.

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Sin(150 + x)+ sin(150 − x) = cos x
77julia77 [94]

Answer:

Below.

Step-by-step explanation:

We need to prove this identity by taking the left  side and trying to transform it to the right side.

LHS = sin(150 + x) + sin(150 − x)

= sin 150 cos x + sin x cos 150 + sin 150 cos x - sin x cos 150

=  2 sin 150 cos x

= 2 * 1/2 * cos x

= cos x = RHS.

So it is proved.

8 0
3 years ago
Find the surface area:
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Algebra 1 Midterm 2021-2022
abruzzese [7]
The answer would be 4! All I did was use a calculator to graph it and it showed
5 0
3 years ago
In this diagram, BAC~ EDF. if the area of BAC = 6 in, what is the area of EDF.
gulaghasi [49]

Answer:

2.7 square inch

Step-by-step explanation:

\triangle BAC \sim \triangle EDF... (Given) \\

\therefore By area of similar triangle theorem:

\frac{A(\triangle BAC)}{A(\triangle EDF)} = \frac{BC^2}{EF^2} \\\\\therefore \frac{6}{A(\triangle EDF)} = \frac{3^2}{2^2} \\\\\therefore \frac{6}{A(\triangle EDF)} = \frac{9}{4} \\\\\therefore A(\triangle EDF) = \frac{4\times 6}{9} \\\\\therefore A(\triangle EDF) = \frac{24}{9} \\\\\therefore A(\triangle EDF) = 2.6667\\\\\huge \purple {\boxed {\therefore A(\triangle EDF) = 2.7\: in^2}}

7 0
4 years ago
What are the values of the three Trigonometric ratio for angle L, in simplest form
bulgar [2K]

\sin\theta=\dfrac{opposite}{hypotenuse}\\\\\cos\theta=\dfrac{adjacent}{hypotenuse}\\\\\tan\theta=\dfrac{opposite}{adjacent}

opposite=20\\\\adjacent=15\\\\hypotenuse=25\\\\\sin L=\dfrac{20}{25}=\dfrac{4}{5}\\\\\cos L=\dfrac{15}{25}=\dfrac{3}{5}\\\\\tan L=\dfrac{20}{15}=\dfrac{4}{3}

3 0
4 years ago
Read 2 more answers
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