Find the product. (z − 2)(z + 2)

8

blagie [28]

Answer:

The new function is g(x) = x² +1

Step-by-step explanation:

Explanation:-

Given that the function f(x) = x²

From graph ,

The parabola y = x² is shifting to up with '1' units

y = x² +1

The new function is g(x) = x² +1

Verification:-

y = x²+1

Put x=0 ⇒ y =1

The point (0,1) lies on the parabola y = x²+1

similarly put x =1 and y = 2

The Point (1,2) lies on the Parabola y = x²+1

∴ The new graph y = x²+1

3 0

3 years ago

Drag each label to the correct location on the table. Each label can be used more than once, but not all labels will be used.

Natalka [10]

Answer:

what lable i dont see nothing

Step-by-step explanation:

7 0

3 years ago

2343 x 23.56 + 94217.23452 / 21421 - 512

monitta

Answer:

54693.47836

Step-by-step explanation:

Order of operations PEMDAS

Do the multiplication and division first - each separately

Then add and subtract the answer you get to get the final answer.

5 0

3 years ago

Read 2 more answers

Select the correct answer.

Rina8888 [55]

A - actuary...........that is the answer

6 0

3 years ago

Read 2 more answers

Based on an indication that mean daily car rental rates may be higher for Boston than for Dallas, a survey of eight car rental c

Elina [12.6K]

Answer:

$t=\frac{(47 -44)-(0)}{3\sqrt{\frac{1}{8}+\frac{1}{9}}}=2.058$

The degrees of freedom are:

$df=8+9-2=15$

And the p value would be:

$p_v =P(t_{15}>2.058) =0.0287$

Since we have a p value lower than the significance level given of 0.05 we can reject the null hypothesis and we can conclude that the true mean for car rental rates in Boston are signiﬁcantly higher than those in Dallas

Step-by-step explanation:

Data given

$n_1 =8$ represent the sample size for group Boston

$n_2 =9$ represent the sample size for group Dallas

$\bar X_1 =47$ represent the sample mean for the group Boston

$\bar X_2 =44$ represent the sample mean for the group Dallas

$s_1=3$ represent the sample standard deviation for group Boston

$s_2=3$ represent the sample standard deviation for group Dallas

We can assume that we have independent samples from two normal distributions with equal variances and that is:

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

Let the subindex 1 for Boston and 2 for Dallas we want to check the following hypothesis:

Null hypothesis: $\mu_1 \leq \mu_2$

Alternative hypothesis: $\mu_1 > \mu_2$

The statistic is given by this formula:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

Where t follows a t student distribution with $n_1+n_2 -2$ degrees of freedom and the pooled variance $S^2_p$ is given by this formula:

$\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

Replacing we got:

$\S^2_p =\frac{(8-1)(3)^2 +(9 -1)(3)^2}{8 +9 -2}=9$

And the deviation would be just the square root of the variance:

$S_p=3$

The statitsic would be:

$t=\frac{(47 -44)-(0)}{3\sqrt{\frac{1}{8}+\frac{1}{9}}}=2.058$

The degrees of freedom are:

$df=8+9-2=15$

And the p value would be:

$p_v =P(t_{15}>2.058) =0.0287$

Since we have a p value lower than the significance level given of 0.05 we can reject the null hypothesis and we can conclude that the true mean for car rental rates in Boston are signiﬁcantly higher than those in Dallas

5 0

3 years ago