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LenaWriter [7]
3 years ago
11

(vi) A solvent extraction in which two ...... liquids move in opposite directions in

Chemistry
1 answer:
ad-work [718]3 years ago
4 0

Answer:

(A). Immmiscible

Liquid/Liquid extraction is a solvent extraction in which two immiscible liquids move in opposite directions are in continuous contact with each other.

Explanation:

A liquid/liquid extraction is a method used to separate mixtures based on relative solubilities in two immiscible liquids, i.e., liquids that do not dissolve in each other but rather form separate layers when placed in the same glassware.

The immiscibility of the liquids is as a result of the two liquids having different polarities. One liquid is polar while the other is non polar, usually water which is polar and an organic solvent which is non-polar. The most common pair of extraction solvents used is diethyl ether or simply ether and water. They separate into layers and the position most each solvent in either the bottom or top layer is determined by its density. Ether is always found on the top layer while water is found innthe bottom layer because ether is less than than water. The density of ether is 0.713 g/cm3 and the density of H2O is 1.0 g/cm3.

The compound to be extracted dissolves into either of the layers based on the principle that like dissolves like. Polar compounds will dissolve into the water layer while organic nor non-polar compounds will dissolve in the ether layer. The compound is the extracted from either of the layer it is dissolved in.

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Which formula is a molecular compound?<br><br> H2O2<br> CaO<br> MgS<br> NaCl
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Electron X can change to a higher energy level or a lower energy level. Which statement is true of electron X?
rosijanka [135]

Answer: 2) Electron X absorbs energy when it changes to a higher energy level.

Explanation:

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(((NEED ANSWER QUICK!!!)))<br><br> Which is the stronger conjugate base, CN- or OCN-? Explain
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The stronger conjugate base will be the weaker acid; i.e., the acid with the smaller Ka-value.

Explanation:

Given conjugate base CN⁻ => weak acid => HCN =>  Ka =4.9 x 10⁻¹⁰

Given conjugate base OCN⁻ => weak acid=> HOCN => Ka = 3.5 x 10⁻⁴

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an aqueous solution contains 1.2mM of total ions. if the solution is NaCl (aq), what is the concentration of chloride ions?
Genrish500 [490]

Explanation:

As the total concentration is given as 1.2 mM. And, it is also given that salt present in the solution is NaCl.

As sodium chloride is an ionic compound so, when it is added to water then it will dissociate into sodium and chlorine ions as follows.

           NaCl \rightarrow Na^{+} + Cl^{-}

So, it means in total there will be formation of 2 ions when one molecules of NaCl dissociates.

Therefore, concentration of chlorine ions will be calculated as follows.

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Thus, we can conclude that the concentration of chloride ions is 0.6 mM.

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