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3 years ago

Given 6.23 mol Al find the atoms of Al

Chemistry

1 answer:

swat323 years ago

3 0

Answer:

The answer is

<h3>3.75 × 10²⁴ atoms of Al</h3>

Explanation:

To find the number of atoms of Al given it's number of moles we use the formula

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question

n = 6.23 mol

We have

N = 6.23 × 6.02 × 10²³

We have the final answer as

<h3>3.75 × 10²⁴ atoms of Al</h3>

Hope this helps you

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3 years ago

What is the frequency of a photon with a wavelength of 3.75×10^-7

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Answer:

Frequency = 0.8×10¹⁵ Hz

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Now we will put the values in formula.

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3 years ago

Given the following information:

Katyanochek1 [597]

Step by Step Explanation

From the question,
the dimensions of the tank are;

L = 30 cm, way =0.075m and H = 15 cm

The density of water is given as
$D = 1g {cm}^{ - 3}$

The unit of density given in the question means that the mass of the water is in grams and the volume should also be in
${cm}^{3}$

To find the volume of the water, we first convert the units of dimensions given in inches and metres to centimetres

$1 inch = 2.54 cm$

This implies that ,

$H=15 inches=15×2.54cm=38.1cm$

Also,

$100cm=1m$

This implies that,
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Now, the volume of water in the tank can hold, can be found from the relation;

$V=L\times W\times H$

This implies that,

$v = 30cm \times (7.5 \times {10}^{ - 4} )cm \times 38.1cm$

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Finally, we can calculate the mass of the water from the relation given;

$D=\frac{M}{V}$

This in implies that

$1g {cm}^{ - 3} = \frac{m}{0.857 {cm}^{3} }$
$m = 1g {cm}^{ - 3} \times 0.857 {cm}^{3}$
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Hence the fish tank can hold 0.857g water.

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