Answer:-
g of carbon dioxide.
Solution:- The balanced equation for the combustion of methane is:
![CH_4+2O_2\rightarrow CO_2+2H_2O](https://tex.z-dn.net/?f=CH_4%2B2O_2%5Crightarrow%20CO_2%2B2H_2O)
There is 1:1 mol ratio between methane and carbon dioxide. Grams of methane are converted to moles and then using mol ratio we get the moles of carbon dioxide that could further be converted to grams. The calculations are shown as:
![6.40*10^-^3gCH_4(\frac{1molCH_4}{16gCH_4})(\frac{1molCO_2}{1molCH_4})(\frac{44gCO_2}{1molCO_2})](https://tex.z-dn.net/?f=6.40%2A10%5E-%5E3gCH_4%28%5Cfrac%7B1molCH_4%7D%7B16gCH_4%7D%29%28%5Cfrac%7B1molCO_2%7D%7B1molCH_4%7D%29%28%5Cfrac%7B44gCO_2%7D%7B1molCO_2%7D%29)
= ![1.76*10^-^2gCO_2](https://tex.z-dn.net/?f=1.76%2A10%5E-%5E2gCO_2)
So, complete combustion of given amount of methane gives
.
The answer is B.
Step By Step Explanation:
Aluminum can be oxidized by
and ![Ca^{2+}](https://tex.z-dn.net/?f=Ca%5E%7B2%2B%7D)
<h3>What is oxidizing?</h3>
Some of the metal corrodes (or oxidizes) and forms the corresponding metal oxide on the surface as a result of a chemical reaction between the metal surface and the oxygen in the air. The corrosion products that occur in some metals, like steel, are highly apparent and loose.
According to reactivity series (The array of metals in the descending order of their reactivities is referred to as the metals' reactivity series. It is sometimes referred to as the metals in the activity series.)
Lithium and calcium ions are more reactive than aluminum ion and they are less electronegative.
Since silver and tin are more electronegative than aluminum so, they cannot oxidize aluminum.
∴
and
ions can oxidize aluminum.
Learn more about electronegativity here brainly.com/question/16446391
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Answer:
OH
Explanation:
The chemical can be assigned the formula OH since it yielded the same volume of hydrogen and oxygen
b) different formula is possible for example consider the two equations below:
2OH → H₂ (g) + O₂(g) and
H₂O₂ → H₂ + O₂
the proportion of hydrogen is the same for both equation, the coefficient can be any number provided it yielded the same proportion.