Answer:
 . 2 m/s
Step-by-step explanation:
Speed is defined as the rate of change in distance per time.
in this case you can simply observe the graph to get the final and initial distances & time.
The motion starts from 0 and moves to 2 if you look at the y axis of the graph. 
Thus, the initial distance is 0m & the final distance is 2m
The time is specified in the question to have an initial of 0 sec and a final of 1 sec.
now let's plot our values out as a given.
S1 = 0m t1 = 0 sec
S2 = 2m t2 = 1 sec
and so you're going to have to find the change in time and displacement individually to later engage both in your formula which is - ∆V = ∆S / ∆t
∆S = S2 - S1 = 2m - 0m = 2m.
∆t = t2 - t1 = 1 sec - 0 sec = 1 sec.
 ∆V = ∆S / ∆t = 2m / 1 sec = 2m/sec (2m/s)
 
        
             
        
        
        
Answer:
I believe its A C D
Step-by-step explanation:
 
        
             
        
        
        
Answer:
See attached
Step-by-step explanation:
The graph of a <u>proportional linear relationship</u> is a line that <u>passes through the origin</u> (0, 0).
From inspection of the given tables, the <u>linear equations</u> for each table of points is:
- Table 1:  y = x + 1
- Table 2:  y = x/2
- Table 3:  y = x + 2
- Table 4:  y = 2x + 1
The only equation for which y = 0 when x = 0 is y = x/2  →  Table 2.
Given points from Table 2:
To <u>graph the line</u>, plot the given points and draw a line through them (see attached).
 
        
             
        
        
        
Answer:
60 kilometers per hour.
420 kilometers will be covered 
Step-by-step explanation:
speed = distance ÷ time.
so 60kmh = 240km divided by 4 Hours
60km = 1 Hour of distance 
240km = 4 Hours of distance
Therefore 60 x 3 hour is 180km added to 240 is 420km. So in 7 hours traveling 60 kilometers per hour the will cover 420kms.
 
        
             
        
        
        
I don't know what the "lowest y-intercept means" so if you can reiterate and clarify I'd appreciate it, but if you understand what you're looking for then I assume that a graph would be helpful. An online useful graphing site I like is desmos. Hope I helped.