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3 years ago

13

-b+10a-5 in standard form

1 answer:

ludmilkaskok [199]3 years ago

7 0

Answer:

10a-b-5

Step-by-step explanation:

-b+10a-5 in standard form

is

10a-b-5

hoped this helped :)

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How do you know that 50 is not a perfect square?

Alexus [3.1K]

We can always do a prime factoring of it, and check

50 = 2*5*5
2*5²

a perfect square, so-called, is the resulting number of a squared value, well 50 is not the result of anything squared, is the result of 3 factors, in this case 2,5 and 5.

a perfect square will be something like say 64, or 144, because

64 = 8*8
8²

144 = 12*12
12²

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2 years ago

Simplify<br> 5m - 7 - 8m + 10

Bogdan [553]

Answer:

−3m + 3

Step-by-step explanation:

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3 years ago

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a wire is bent into the shape of a square, each side is 5 in long. then the wire is now bent to the shape of a rectangle if the

Luda [366]

Answer:

4 inches

Step-by-step explanation:

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2 years ago

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Consider a Triangle ABC like the one below. Suppose that C = 98, A = 74, and b = 11 (figure is not drawn to scale.) solve the tr

Degger [83]

Answer:

$A=73.8\°$

$B=8.2\°$

$c=76.3\ units$

Step-by-step explanation:

step 1

Find the measure of side c

Applying the law of cosines

$c^{2}= a^{2}+b^{2}-2(a)(b)cos(C)$

substitute the given values

$c^{2}= 74^{2}+11^{2}-2(74)(11)cos(98\°)$

$c^{2}=5,823.5738$

$c=76.3\ units$

step 2

Find the measure of angle A

Applying the law of sine

$\frac{a}{sin(A)}=\frac{c}{sin(C)}$

substitute the given values

$\frac{74}{sin(A)}=\frac{76.3}{sin(98\°)}$

$sin(A)=(74)sin(98\°)/76.3$

$A=arcsin((74)sin(98\°)/76.3)$

$A=73.8\°$

step 3

Find the measure of angle B

we know that

The sum of the internal angles of a triangle must be equal to 180 degrees

so

$A+B+C=180\°$

substitute the given values

$73.8\°+B+98\°=180\°$

$171.8\°+B=180\°$

$B=180\°-171.8\°=8.2\°$

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3 years ago

Rewrite each number sentence using numerals and symbols. Find the difference between 4 and 3 and then add 7 *

Zina [86]

Answer:

8

Step-by-step explanation:

4-3+7=8

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3 years ago