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abruzzese [7]
2 years ago
12

Estimate 5171 / 17 by first rounding each number so that it has only 1 nonzero digit.

Mathematics
2 answers:
padilas [110]2 years ago
8 0

Answer:

250

Step-by-step explanation:

5171/17

Estimate: 5000/20 = 500/2 = 250

german2 years ago
7 0

Answer:

250

Step-by-step explanation:

round first to 5000/20 = 250

please give a brainiest

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Daniel [21]

Answer:

Near 3.2

Step-by-step explanation:

6 0
3 years ago
Could you please help me for this question?
Olin [163]

Answer:

  See attached for graphs

  g(x) -- domain: -∞ < x < ∞; range: 0 < y < ∞

  g^-1(x) -- domain: 0 < x < ∞; range: -∞ < y < ∞

Step-by-step explanation:

g(x) is an exponential decay function. Its base is 1/3, so each increase of 1 unit in x will multiply the y-value by a factor of 1/3. The graph will rapidly approach its horizontal asymptote of y=0 as x gets large. The y-intercept is (0, 1). Just as y gets smaller as x increases, so it gets larger as x decreases. Each decrease of x by 1 unit causes the y-value to be multiplied by 3.

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The graph of g^-1(x) is the graph of g(x) reflected across the line y=x. That is, each coordinate pair (x, y) on the graph of g(x) becomes a point (y, x) on the graph of the inverse function. In order to graph g^-1(x), you don't need to write down the function, you only need to know the relationship between the graphs.

Just as x- and y- are interchanged on the graph, so the domain, range, and intercepts are interchanged. g^-1(x) will have a vertical asymptote of x=0, and an x-intercept of (1, 0). The domain of g^-1(x) is the range of g(x): 0 < x < ∞; and the range of g^-1(x) is the domain of g(x): -∞ < y < ∞.

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The attached graph shows g(x) in red and g^-1(x) in blue. As you can see, we created the graph simply by interchanging x and y. The line y=x is shown for reference, so you can see that each curve is a reflection of the other across that line.

_____

<em>Additional comment</em>

The explicit expression for g^-1(x) can be found by solving for y:

  x = g(y)

  x=\left(\dfrac{1}{3}\right)^y=\dfrac{1}{3^y}=3^{-y}\\\\ \log(x)=-y\cdot\log(3)\qquad\text{take logarithms}\\\\y=-\dfrac{\log{x}}{\log{3}}=-\log_3{x}\qquad\text{use the change of base relation}\\\\\boxed{g^{-1}(x)=-\log_3{x}}

If you're familiar with the log function, you know it has an x-intercept of 1 and a vertical asymptote at x=0. The base of the log function is simply a vertical scale factor. The minus sign reflects it across the x-axis.

6 0
2 years ago
Which expression can be used to find the surface area of the following rectangular prism?
Ivenika [448]

Answer:

B

Step-by-step explanation:

6+6+10+10+15+15

4 0
3 years ago
Read 2 more answers
Determine which postulate or theorem can be used to prove that<br> REM= DME.
Snowcat [4.5K]

Answer:

SSS

Step-by-step explanation:

REM and DME share a side. This side is of course congruent.

In addition, sides RM and ED are marked as congruent, as are RE and MD.

All three corresponding sides of each triangle are congruent, which proves the triangles' congruency.

No information is given about the angles in these triangles, so none of the other theorem answer choices are valid.

Please mark brainliest! :)

5 0
2 years ago
Read 2 more answers
Compare the values of the underlined digits.
Fantom [35]

To solve this problem, you have to determine the value of the number 3 in both numbers:

6,300 – the number 3 is in the hundreds place so its value is 300

530 – the number 3 is in the tens place so its value is 30

To answer the question, the value of 3 in 6,300 is 10 times the value of 3 in 530.

7 0
3 years ago
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