Multipy (2x + 4 (x - 4) Zzz

larisa [96]

The empty jug weighs 0.75 lb

With the 3c, the total weighs 2.25 lb. That means:

3c + empty jug = 3c + 0.75 = 2.25

3c = 2.25 - 0.75
3c = 1.5
and 1c = 0.5 (so c is a constant -or the slope-)

Then the equation is:

y = 0.5x + 0.75

4 0

3 years ago

PLEASE HELP, WILL GIVE BRAINLIEST IF CORRECT!!!! (08.06 MC) Mike and his friends bought cheese wafers for $2 per packet and choc

maks197457 [2]

Answer:

x = 5 , y = 15

Step-by-step explanation:

You can solve this using substitution.

Let the quantity of cheese wafers be denoted by x and the quantity of chocolate wafers denoted by y

2x + 1y = 25

x + y = 20

These two equations are the answer to part A, (remember to include the above prompt which says what x and y denote).

For part B I used substitution because it was more applicable to the question then addition or elimination.

ACTUAL WORK

Set 2x + 1y = 25 equal to x

x = 25 - y / 2

Replace x with y in the second equation

(25 - y / 2) + y = 20

And solve for y

y = 15

Since we know what y is we can replace y in the second equation and find what x is

x + 15 = 20

Solve for x

x = 5

8 0

3 years ago

Please help logarithms!

nlexa [21]

Given:

$\log_34\approx 1.262$

$\log_37\approx 1.771$

To find:

The value of $\log_3\left(\dfrac{4}{49}\right)$ .

Solution:

We have,

$\log_34\approx 1.262$

$\log_37\approx 1.771$

Using properties of log, we get

$\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349$ $\left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]$

$\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2$

$\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37$ $[\log x^n=n\log x]$

Substitute $\log_34\approx 1.262$ and $\log_37\approx 1.771$ .

$\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)$

$\log_3\left(\dfrac{4}{49}\right)=1.262-3.542$

$\log_3\left(\dfrac{4}{49}\right)=-2.28$

Therefore, the value of $\log_3\left(\dfrac{4}{49}\right)$ is $-2.28$ .

5 0

3 years ago

Expanding polynomial functions using binomial theorem or pascals triangle

konstantin123 [22]

Answer:

The formula for Pascal's Triangle comes from a relationship that you yourself might be able to see in the coefficients below.

(x + y)0 (x + y)1 (x + y)² (x + y)3 (x + y)41 x + y x² + 2xy + y² x3 + 3x2Y + 3xY2 + y3 x4 + 4x3Y + 6x2Y2 + 4XY3 + Y4

HOPE THIS HELPS!

7 0

3 years ago

Given a triangle MTN, prove that

cupoosta [38]

Answer:

$\angle m + \angle t + \angle n = 180$

Step-by-step explanation:

Required

Show that:

$\angle m + \angle t + \angle n = 180^o$

To make the proof easier, I've added a screenshot of the triangle.

We make use of alternate angles to complete the proof.

In the attached triangle, the two angles beside $\angle m$ are alternate to $\angle t$ and $\angle n$

i.e.

$\angle 1 = \angle t$

$\angle 2 = \angle n$

Using angle on a straight line theorem, we have:

$\angle 1 + \angle m + \angle 2 = 180$

Substitute values for (1) and (2)

$\angle t + \angle m + \angle n = 180$

Rewrite as:

$\angle m + \angle t + \angle n = 180$ -- proved

5 0

3 years ago