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3 years ago

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Use the graphing calculator to locate the solutions of this system of equations: y = x2 + x – 2 y = –x + 1 What are the solution

s? (–3, 4) and (0,1) (–3, 4) and (–1,0) (3, –4) and (1,0) (–3, 4) and (1,0)

2 answers:

mamaluj [8]3 years ago

7 0

By using a graphing calculator, the solutions are:

(-3, 4) and (1, 0)

ludmilkaskok [199]3 years ago

7 0

Answer:

the answer is D

Step-by-step explanation:

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(8y²)(-3x²y²)(2/3xy⁴)<br><br> HELP PLEASEEEEEEEE

IRINA_888 [86]

Step-by-step explanation:

1 Remove parentheses.

8{y}^{2}\times -3{x}^{2}{y}^{2}\times \frac{2}{3}x{y}^{4}

8y

2

×−3x

2

y

2

×

3

2

xy

4

2 Use this rule: \frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}

b

a

×

d

c

=

bd

ac

.

\frac{8{y}^{2}\times -3{x}^{2}{y}^{2}\times 2x{y}^{4}}{3}

3

8y

2

×−3x

2

y

2

×2xy

4

3 Take out the constants.

\frac{(8\times -3\times 2){y}^{2}{y}^{2}{y}^{4}{x}^{2}x}{3}

3

(8×−3×2)y

2

y

2

y

4

x

2

x

4 Simplify 8\times -38×−3 to -24−24.

\frac{(-24\times 2){y}^{2}{y}^{2}{y}^{4}{x}^{2}x}{3}

3

(−24×2)y

2

y

2

y

4

x

2

x

5 Simplify -24\times 2−24×2 to -48−48.

\frac{-48{y}^{2}{y}^{2}{y}^{4}{x}^{2}x}{3}

3

−48y

2

y

2

y

4

x

2

x

6 Use Product Rule: {x}^{a}{x}^{b}={x}^{a+b}x

a

x

b

=x

a+b

.

\frac{-48{y}^{2+2+4}{x}^{2+1}}{3}

3

−48y

2+2+4

x

2+1

7 Simplify 2+22+2 to 44.

\frac{-48{y}^{4+4}{x}^{2+1}}{3}

3

−48y

4+4

x

2+1

8 Simplify 4+44+4 to 88.

\frac{-48{y}^{8}{x}^{2+1}}{3}

3

−48y

8

x

2+1

9 Simplify 2+12+1 to 33.

\frac{-48{y}^{8}{x}^{3}}{3}

3

−48y

8

x

3

10 Move the negative sign to the left.

-\frac{48{y}^{8}{x}^{3}}{3}

−

3

48y

8

x

3

11 Simplify \frac{48{y}^{8}{x}^{3}}{3}

3

48y

8

x

3

to 16{y}^{8}{x}^{3}16y

8

x

3

.

-16{y}^{8}{x}^{3}

−16y

8

x

3

Done

6 0

2 years ago

Find the slope of the lines. Are the 2 lines parallel or perpendicular? Explain how you can use the slope of two lines to tell i

rewona [7]

Answer:

slope = $\frac{3}{7}$ and - $\frac{7}{3}$ , perpendicular

Step-by-step explanation:

the equation of a line in slope-intercept form is

y = mx + c ( m is the slope and c the y-intercept )

y = $\frac{3}{7}$ x + 11 is in this form with m = $\frac{3}{7}$

Rearrange 7x + 3y = 13 into this form

subtract 7x from both sides

3y = - 7x + 13 ( divide all terms by 3 )

y = - $\frac{7}{3}$ x + $\frac{13}{3}$ ← in slope- intercept form

with m = - $\frac{7}{3}$

• Parallel lines have equal slopes

• The product of perpendicular slopes = - 1

The lines are not parallel since slopes are not equal

$\frac{3}{7}$ × - $\frac{7}{3}$ = - 1

Hence lines are perpendicular

6 0

3 years ago

An equation in the form ax2+bx+c=0 is solved by the quadratic formula. The solution to the equation is shown below.x=−7±√ "572"

7nadin3 [17]

Answer:

B: a = 1, b= 7, c = -2

Explanation:

$\sf Quadratic \ Equation : \dfrac{-b\pm \sqrt{b^2 - 4ac} }{2a}$

Knowing This:

<u>solve for b</u>

-b = -7

b = 7

<u>solve for a</u>:

2a = 2

a = 1

<u>solve c</u>:

b² - 4ac = 57

7² - 4(1)(c) = 57

-4c = 57 - 49

-4c = 8

c = 8/-4 = -2

4 0

1 year ago

Read 2 more answers

What’s the slope of x+2y=-8?

mash [69]

Answer:

- 1/2

Step-by-step explanation:

We use the slope-intercept form to figure out our slope.

y = mx + b

Get y alone:

x + 2y = -8

2y = -x - 8

y = -x/2 - 4

Since m is the slope in y = mx + b, we can see that -1/2 is in the place of m, therefore our slope is -1/2

7 0

2 years ago

The graph of a function f(x) passes through the following points:

Alex

The function is f(x) = -2x² + 2 if the function f(x) passes through the following points:(0,2), (1, 0), (-1,0)

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have:

The graph of a function f(x) passes through the following points: (0,2), (1, 0), (-1,0)

Let

f(x) = ax² + bx + c

Plug x = 0, and y = 2

c = 2 ...(1)

Plug x = 1 and y = 0

a + b + c = 0 ..(2)

Plug x = -1 and y = 0

a - b + c = 0 ...(3)

After solving (1), (2), and (3)

a = -2

b = 0

c = 2

f(x) = -2x² + 2

Thus, the function is f(x) = -2x² + 2 if the function f(x) passes through the following points:(0,2), (1, 0), (-1,0)

Learn more about the function here:

brainly.com/question/5245372

#SPJ1

5 0

2 years ago