2 years ago

FREEEEEEEEEEEEEEEEE POINTTTTTSsssssssssssssssssssssssssssssss

SAT

2 answers:

Karolina [17]2 years ago

4 0

Answer:

hi thank you

Explanation:

Happy Holidays

Sedaia [141]2 years ago

4 0

Here ya go c=69, also thanks mate

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A(t)=(t−k)(t−3)(t−6)(t+3) Given that a(2)=0 , what is the absolute value of the product of the zeros of a?

Ugo [173]

So using a(2)=0 we can first solve for k by substituting t for 2
0 = (2-k)(2-3)(2-6)(2+3)
0 = (2-k)(-1)(-4)(5)
0 = (2-k)20
0 = 40 - 20k
-40 = -20k
k = 2

The next step would be to find all the 0s of a.
0 = (t-2)(t-3)(t-6)(t+3)
T = 2,3,6,-3

Then we find the product
2x3x6x-3 = -108

Since the problem asks for the absolute value, the answer is positive 108

6 0

2 years ago

An ninh hàng không được xem là yếu tố sống còn của ngành hàng không trong mối liên

AlladinOne [14]

Explanation:

Theo Anh (Chị), tại sao nói An ninh hàng không

được xem là yếu tố sống còn ? Đảm bảo an ninh hàng không là gì ?

8 0

2 years ago

Soon Yi loves to bake, and she is making flaky pastry. Soon Yi starts with a layer of dough 222 millimeters (\text{mm})(mm)left

frozen [14]

Answer:

3 times

Explanation:

When the dough is folded, it increases by a constant factor. We can model the growth of the thickness using the exponential growth model

$T(n)=T_0(1+r)^n$

Where:

Initial thickness, $T_0$ = 2mm

Growth factor, r =8%=0.08

We want to find the smallest number of times Soon Yi will have to roll and fold the dough so that the resulting dough is at least 2.5mm.

i.e When $T(n)\geq 2.5$ mm$

$2(1+0.08)^n\geq 2.5\\2(1.08)^n\geq 2.5\\$Divide both sides by 2$\\\dfrac{2(1.08)^n}{2}\geq \dfrac{2.5}{2}\\\\1.08^n\geq 1.25\\\\$Change to logarithm form\\n \geq \log_{1.08}1.25\\\\n\geq \dfrac{\log 1.25}{\log 1.08} \\\\n\geq 2.9$