Answer:
The wall is 90 meters wide.
Step-by-step explanation:
1. set up and solve a proportion to find the value of w like this:
1cm=6cm
15m=wm
2. cancel out the like units on both sides of the equation
1=6
15=w
3. Equate the cross products, and then solve for w:
1*w=15*6
w=90 The actual width of the wall is 90 meters.
Answer:
ac+ad+bc+bd
Step-by-step explanation:
PLS mark me brainiest
You are correct!
Step 1:Write what you know
Madeline's Height: 6 ftMadeline's Shadow: 108 in
Friend's Height: X (we use X as a variable because his height is unknown)Friend's Shadow: 108 in - 1.5 ft 108 in - 18 in 90 in
Step 2:Set up proportions
6 x----- = -----108 90
Step 3:Cross Multiply & Solve
108x = 540x = 5 ft tall
Answer:
<I= 15degrees
Step-by-step explanation:
Using the cosine rule formulae;
j² = i²+k²-2i cos <J
j² = 37²+57² - 2(37)(57)cos <141
j² = 1369+ 3249- 4218cos <141
j² = 4618- 4218cos <141
j² = 4618-(-3,278)
j²= 7,896
j = √7,896
j = 88.86inches
Next is to get <I
i² = j²+k²-2jk cos <I
37² = 88.86²+57² - 2(88.86)(57)cos <I
1369 = 7,896.0996+ 3249- 10,130.04cos <I
1369 = 11,145.0996 - 10,130.04cos <I
1369 - 11,145.0996 = - 10,130.04cos <I
-9,776.0996=- 10,130.04cos <I
cos <I =9,776.0996 /10,130.04
cos<I = 0.96506
<I = 15.19
<I= 15degrees
y = -1/2x + 5 should be your equation because it is 5 ft above sea level and its eroding, or going down, 1 ft per 20 years. So every year, the sand dune erodes 1/20 ft more.
Hope this helps!
