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Vitek1552 [10]
3 years ago
5

Ill give brainliest!! just please help!!

Mathematics
1 answer:
goldfiish [28.3K]3 years ago
5 0

Answer:

x=4

Other stuff:

Don't  if it is incorrect or if it was the answer. the image was blurry.

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What is 11 3\5 + 6 4\15
SOVA2 [1]
So what i would do is take 3/5 and multiply is all by 3 so you end up with 9/15.
Now after you have done that  do this,  9/15+ 4/15. Add 9/15 and 4/15 together which has a sum of 13/15 now add 11 + 6 which is 17 then add in the 13/15 and you get the answer of 17 13/15
8 0
3 years ago
Which ordered pair could be removed from the graph to create a set of ordered pairs that represents a function?
pochemuha
(1,3) hope it helps you good luck
4 0
4 years ago
Read 2 more answers
Select the correct answer. Let f(x) and g(x) be polynomials as shown below. <br>​
tia_tia [17]

Answer:

f(x) and g(x) are closed under multiplication because when multiplied, the result remains a polynomial.

Step-by-step explanation:

First, to be closed means that once an operation has commenced, the result is a polynomial, just like the two original ones.

When polynomials are multiplied, exponents simply add together, and constants are multiplied. A polynomial is a finite sum of terms in which all variables have whole numbered exponents.

In this scenario, when we multiply polynomials, exponents are solely added together, and one whole number plus another is still a whole number. Similarly, constants multiplied by constants stay as constants, and constants multiplied by variables keeps it in polynomial form. (e.g. 3 * x² makes it 3x², and 3x² is fine in a polynomial).

Therefore, given these facts, f(x) and g(x) are closed under multiplication because when multiplied, the result remains a polynomial.

7 0
3 years ago
Please help fast I will add more points
jasenka [17]

Answer:

C

Step-by-step explanation:

Under a reflection in the y- axis

a point (x, y ) → (- x, y ) , then

A(- 1, 3 ) → A'(1, 3 ) → C

8 0
3 years ago
Given is a finite set of spherical planets, all of the same radius and no two intersecting. On the surface of each planet consid
wariber [46]

Answer:

Step-by-step explanation:

To answer this question, First, we define a direction in space, which defines

the North Pole of each planet.

We also assume that the direction is not at 90° perpendicular to the axis of any two planet.

Assume we now define an order on the set of planet by saying that planet A ≥ B, when removing all the other planet from space, the north pole B, is visible from A.

If we refer to the direction of the planet in the diagram, we discover that,

1, A ≥ A

2, If A ≥ B and B≥ A,

Then A = B

3, If A ≥ B, and B ≥ C , then A ≥ C

4, Either A ≥ B or B ≥ A

It should also be noted that the array of order above has a unique maximal element  (M). This is the only  planet whose North Pole is not visible from another.

If we now consider a sphere of the same radius as the planets. Remove

from it all North Poles defined by directions that are perpendicular

to the axis of two of the planets. This is a set of area zero.

For every other point on this sphere, there exists a direction in

space that makes it the North Pole, and for that direction, there

exists a unique North Pole on one of the planets which is not visible

from the others. Hence the total area of invisible points is equal

to the area of this sphere, which in turn is the area of one of the  planets.

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3 years ago
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