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timurjin [86]
3 years ago
11

(11 + 5) + 52 × (12 − 10)

Mathematics
1 answer:
melomori [17]3 years ago
5 0

Answer:

120

Step-by-step explanation:

11+5+52(12−10)

=16+52(12−10)

=16+(52)(2)

=16+104

=120

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What is the equation if its Slope= -3/5, y-intercept =2
Oksana_A [137]

Answer:

y = -3/5x +2

Step-by-step explanation:

y = mx + b

where m is the slope and b is the y intercept

y = -3/5x + 2

3 0
3 years ago
This is my last question i promise
VladimirAG [237]

Answer:

ok

Step-by-step explanation:

x+7+25+2x+4=180

3x+11+25=180

3x=180-36

3x=144

<em>x</em><em>=</em><em>1</em><em>4</em><em>4</em><em>/</em><em>3</em>

<em>x</em><em>=</em><em>4</em><em>8</em>

6 0
3 years ago
Worth 20 points!! If you answer wrong or something not related to the question I will report you! Thanks :)
KonstantinChe [14]

A

f(x) = 2x + 1

f(3) = 2*3 + 1 = 7

B

g(x) = x^2

g(7) = 7^2

g(7)= 49

C

f(g(x)) = 2(g(x) + 1

f(g(x)) = 2 x^2 + 1

f(g(3) = 2* 3^2 + 1

f(g(3) = 19

D

g(f(x)) = (f(x))^2

g(f(x)) = (2x + 1)^2

g(f(3)) = (2*3 + 1)^2 = (6 + 1)^2 = 49

E

f(g(x)) = 2*g(x) + 1

f(g(x)) = 2*x^2 + 1

f(g(3)) = 2*3^2 + 1

f(g(3)) = 2 * 9 + 1

f(g(3)) = 18 + 1

f(g(3) = 19

F

f(g(x)) = 2(g(x)) + 1

f(g(x)) = 2*x^2 + 1  

4 0
3 years ago
QS bisects &lt;PQR. If m&lt;PQS = 5x and m&lt;RQS = 2x + 6, then what is m&lt;PQR?​
Varvara68 [4.7K]

Answer:

20 degrees

Step-by-step explanation:

If QS bisects Angle PQR, it would mean that Angle PQS and Angle RQS are equal

2x+6=5x

Subtract 2x on both sides

6=3x

Divide by 3 on both sides

x=2

Plug the value of x into either one of the angle measures equation

5x

5(2)=10

If they are equal to one another it would mean that the other angle would be the same measure and you would multiply it by 2

10(2)=20

Therefore 20 degrees is the answer for the measure of Angle PQR

Hope it helped :))

5 0
3 years ago
Find dx/dt when y=2 and dy/dt=1, given that x^4=8y^5-240<br><br> dx/dt=
katrin2010 [14]

Answer:

The value of \frac{dx}{dt} is \frac{160}{x^3}.

Step-by-step explanation:

The given equation is

x^4=8y^5-240

We need to find the value of \frac{dx}{dt}.

Differentiate with respect to t.

4x^3\frac{dx}{dt}=8(5y^4)\frac{dy}{dt}-0              [\because \frac{d}{dx}x^n=nx^{n-1},\frac{d}{dx}C=0]

4x^3\frac{dx}{dt}=40y^4\frac{dy}{dt}

It is given that y=2 and dy/dt=1, substitute these values in the above equation.

4x^3\frac{dx}{dt}=40(2)^4(1)

4x^3\frac{dx}{dt}=40(16)(1)

4x^3\frac{dx}{dt}=640

Divide both sides by 4x³.

\frac{dx}{dt}=\frac{640}{4x^3}

\frac{dx}{dt}=\frac{160}{x^3}

Therefore the value of \frac{dx}{dt} is \frac{160}{x^3}.

4 0
3 years ago
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