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Mathematics

1 answer:

Kitty [74]2 years ago

5 0

Answer:

Please check the explanation.

Step-by-step explanation:

Ascending Order:

When we talk about the numbers to be arranged in ascending order, it means the numbers need to be arranged from smallest to largest.

For example, if we have to arrange the numbers from 1 to 5 in ascending order.

It means, the ascending order will be: 1, 2, 3, 4, 5

Now, let us arrange the given numbers in ascending order.

a) 2234 to 2238 2234 2235 2236 2237 2238

b) 4099 to 4103 4099 4100 4101 4102 4103

c) 3298 to 3302 3298 3299 3300 3301 3302

d) 7269 to 7273 7269 7270 7271 7272 7273

e) 6354 to 6358 6354 6355 6356 6357 6358

f) 8379 to 8383 8379 8380 8381 8382 8383

g) 7365 to 7369 7365 7366 7367 7368 7369

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Draw the triangle with vertices a(1, 1), b(5, 3), c(1, 7). find the parametrization, including endpoints, and sketch to check. (

Firlakuza [10]

Part A:

The parametric equations $x=x_1+(x_2-x_1)t$ and $y=y_1+(y_2-y_1)t$ where $0\leq t\leq1$ describes the line segment that joins the points $(x_1,\ y_1)$ and $(x_2,\ y_2)$ .

The parameterization of the line joining points A(1, 1) and B(5, 3) are given by substituting $x_1=1,\ \ y_1=1,\ \ x_2=5,\ \ y_2=3$ .

Thus, we have

x = 1 + (5 - 1)t = 1 + 4t
y = 1 + (3 - 1)t = 1 + 2t

Therefore, the parameterization of line joining points A(1, 1) and B(5, 3) are x = 1 + 4t and y = 1 + 2t.

Part B:

The parametric equations $x=x_1+(x_2-x_1)t$ and $y=y_1+(y_2-y_1)t$ where $0\leq t\leq1$ describes the line segment that joins the points $(x_1,\ y_1)$ and $(x_2,\ y_2)$ .

The parameterization of the line joining points B(5, 3) and C(1, 7) are given by substituting $x_1=5,\ \ 
y_1=3,\ \ x_2=1,\ \ y_2=7$ .

Thus, we have

x = 5 + (1 - 5)t = 5 - 4t
y = 3 + (7 - 3)t = 3 + 4t

Therefore, the parameterization of line joining points B(5, 3) and C(1, 7) are x = 5 - 4t and y = 3 + 4t.

Part C:

The parametric equations $x=x_1+(x_2-x_1)t$ and $y=y_1+(y_2-y_1)t$ where $0\leq t\leq1$ describes the line segment that joins the points $(x_1,\ y_1)$ and $(x_2,\ y_2)$ .

The parameterization of the line joining points C(1, 7) and A(1, 1) are given by substituting $x_1=1,\ \ 
y_1=7,\ \ x_2=1,\ \ y_2=1$ .

Thus, we have

x = 1 + (1 - 1)t = 1
y = 7 + (1 - 7)t = 7 - 6t

Therefore, the parameterization of line joining points A(1, 1) and B(5, 3) are x = 1 and y = 7 - 6t.

8 0

3 years ago

PLEASE HELP [[99 POINTS!!!!!!}

LekaFEV [45]

I think the answer is D because its multiplying by 2 each time

5 0

3 years ago

Read 2 more answers

A ladder 15 feet from the base of a building reaches a window that is 35 feet high. What is the length of the ladder to the near

nikdorinn [45]

All you do is use the a+b=c formula lets plug it in
15+b=35
15+20=35
35=35
The answer is 20

7 0