Answer:
y =(v-4)^2 -4
Step-by-step explanation:
vertex form of a parabola is
y = a (v-h)^2 +k
where (h,k) is the vertex
y =a(v-4)^2 +(-4)
y =a(v-4)^2 -4
now substitute another point in to determine a
let's pick 0, 12
12 = a((0-4)^2 -4
add 4 to each side
16 = a * (-4)^2
16 = a*16
divide by 16
a = 1
substitute in what we know
y =1 *(v-4)^2 -4
y =(v-4)^2 -4
K = 10
I think. I’m not positive sure though. Hope this helped!
Answer:
im confused
Step-by-step explanation:
im confused whats your question tho
Answer:
D.
Step-by-step explanation:
The solution is where the lines intersect which is at the point (3,2).
So the answer is Option D.
The point (3,2) satisfies both equations.
