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2 years ago

Is there no solution, one solution or many solutions for 21+2.5w=6+5.7w-3.2w+15?

1 answer:

6 0

There are many solutions. infinite solutions at that. when you solve it it equals itself 2.5w+21= 2.5w+21 so that means all numbers would work as a solution.

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Pls help ASAP

soldier1979 [14.2K]

Answer:

Sample response:

To determine the relationship between quantities, you must determine what to do to the x-values to make them into y-values. The correct operation must turn every x-value into the corresponding y- value in the table. Once you know the relationship, you can use the same operation on all of the x-values that have unknown y-values.

OR:

In a table to get from x to y you have to multiply by a number. To find this you must divide x by y or y by x. So to get the missing quantities you must multiply the last known number by the number you found by dividing.

3 0

2 years ago

Read 2 more answers

Can you help me with number 2,3,4,5,6. Don't worry they are only fractions they are not questions that need to be explained. Als

joja [24]

2. 1/3 + 1/3 = 2/3
2/6 + 2/6 = 4/6 = 2/3
1/3 + 2/6 = 2/3

3. 3/6 - 2/6 = 1/6 2/2 - 1/2 = 1/2
2/3 - 1/6 = 1/2 5/6 - 1/2 = 1/3

8 0

2 years ago

Read 2 more answers

Tony has a bag containing five balls: one red, one blue, one

Ratling [72]

Answer:

20 percent

Step-by-step explanation:

100(%) (all 5 balls) ÷ 5 = 20(%)

5 0

2 years ago

Read 2 more answers

Find the point (,) on the curve =8 that is closest to the point (3,0). [To do this, first find the distance function between (,)

ELEN [110]

Question:

Find the point (,) on the curve $y = \sqrt x$ that is closest to the point (3,0).

[To do this, first find the distance function between (,) and (3,0) and minimize it.]

Answer:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

Step-by-step explanation:

$y = \sqrt x$ can be represented as: $(x,y)$

Substitute $\sqrt x$ for $y$

$(x,y) = (x,\sqrt x)$

So, next:

Calculate the distance between $(x,\sqrt x)$ and $(3,0)$

Distance is calculated as:

$d = \sqrt{(x_1-x_2)^2 + (y_1 - y_2)^2}$

So:

$d = \sqrt{(x-3)^2 + (\sqrt x - 0)^2}$

$d = \sqrt{(x-3)^2 + (\sqrt x)^2}$

Evaluate all exponents

$d = \sqrt{x^2 - 6x +9 + x}$

Rewrite as:

$d = \sqrt{x^2 + x- 6x +9 }$

$d = \sqrt{x^2 - 5x +9 }$

Differentiate using chain rule:

Let

$u = x^2 - 5x +9$

$\frac{du}{dx} = 2x - 5$

So:

$d = \sqrt u$

$d = u^\frac{1}{2}$

$\frac{dd}{du} = \frac{1}{2}u^{-\frac{1}{2}}$

Chain Rule:

$d' = \frac{du}{dx} * \frac{dd}{du}$

$d' = (2x-5) * \frac{1}{2}u^{-\frac{1}{2}}$

$d' = (2x - 5) * \frac{1}{2u^{\frac{1}{2}}}$

$d' = \frac{2x - 5}{2\sqrt u}$

Substitute: $u = x^2 - 5x +9$

$d' = \frac{2x - 5}{2\sqrt{x^2 - 5x + 9}}$

Next, is to minimize (by equating d' to 0)

$\frac{2x - 5}{2\sqrt{x^2 - 5x + 9}} = 0$

Cross Multiply

$2x - 5 = 0$

Solve for x

$2x =5$

$x = \frac{5}{2}$

Substitute $x = \frac{5}{2}$ in $y = \sqrt x$

$y = \sqrt{\frac{5}{2}}$

Split

$y = \frac{\sqrt 5}{\sqrt 2}$

Rationalize

$y = \frac{\sqrt 5}{\sqrt 2} * \frac{\sqrt 2}{\sqrt 2}$

$y = \frac{\sqrt {10}}{\sqrt 4}$

$y = \frac{\sqrt {10}}{2}$

Hence:

$(x,y) = (\frac{5}{2},\frac{\sqrt{10}}{2}})$

3 0

3 years ago

Three students scheduled interviews for summer employment at the Brookwood Institute. In each case the interview results in eith

adoni [48]

Answer:

a. 8 outcomes

b. Discrete Variable

c. See explanation below

Step-by-step explanation:

Let N = No Offers made

Let Y = Offers made

The Expected outcome are as follows:

NNN, NNY, NYN, YNN, NYY, YNY, YYN, YYY

= 8

Let x = number of offers made

X is said to be discrete if x can take values that are restricted to a defined or limited values

X is said to be continuous if x can take a range of values that is not restricted to any range(i.e. continuous)

Looking at the brief description above, we can conclude that x is discrete

NNN, 0

NNY, 1

NYN, 1

YNN, 1

NYY, 2

YNY, 2

YYN, 2

YYY, 3

Where 0 to 3 represents number of offers at every instance

5 0

2 years ago