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bearhunter [10]

3 years ago

7

Write the ratio in simplest form: 27 red markers to 12 blue markers

1 answer:

elena-14-01-66 [18.8K]3 years ago

6 0

What do you mean by this? Do you have a picture

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A chord consists of notes that sound good together. The C major chord, starting at middle C, has the following

guajiro [1.7K]

Answer:

D. 3

Step-by-step explanation:

I mathed it

7 0

3 years ago

Use synthetic division to find (5x<br> + 31x + 32) = (x + 5).

LiRa [457]

We move all terms to the left:
+31x+32)-((+5)=0
So your answer is 0

5 0

3 years ago

Given tan theta =9, use trigonometric identities to find the exact value of each of the following:_______

Ludmilka [50]

Answer:

$(a)\ \sec^2(\theta) = 82$

$(b)\ \cot(\theta) = \frac{1}{9}$

$(c)\ \cot(\frac{\pi}{2} - \theta) = 9$

$(d)\ \csc^2(\theta) = \frac{82}{81}$

Step-by-step explanation:

Given

$\tan(\theta) = 9$

Required

Solve (a) to (d)

Using tan formula, we have:

$\tan(\theta) = \frac{Opposite}{Adjacent}$

This gives:

$\frac{Opposite}{Adjacent} = 9$

Rewrite as:

$\frac{Opposite}{Adjacent} = \frac{9}{1}$

Using a unit ratio;

$Opposite = 9; Adjacent = 1$

Using Pythagoras theorem, we have:

$Hypotenuse^2 = Opposite^2 + Adjacent^2$

$Hypotenuse^2 = 9^2 + 1^2$

$Hypotenuse^2 = 81 + 1$

$Hypotenuse^2 = 82$

Take square roots of both sides

$Hypotenuse =\sqrt{82}$

So, we have:

$Opposite = 9; Adjacent = 1$

$Hypotenuse =\sqrt{82}$

Solving (a):

$\sec^2(\theta)$

This is calculated as:

$\sec^2(\theta) = (\sec(\theta))^2$

$\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2$

Where:

$\cos(\theta) = \frac{Adjacent}{Hypotenuse}$

$\cos(\theta) = \frac{1}{\sqrt{82}}$

So:

$\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2$

$\sec^2(\theta) = (\frac{1}{\frac{1}{\sqrt{82}}})^2$

$\sec^2(\theta) = (\sqrt{82})^2$

$\sec^2(\theta) = 82$

Solving (b):

$\cot(\theta)$

This is calculated as:

$\cot(\theta) = \frac{1}{\tan(\theta)}$

Where:

$\tan(\theta) = 9$ ---- given

So:

$\cot(\theta) = \frac{1}{\tan(\theta)}$

$\cot(\theta) = \frac{1}{9}$

Solving (c):

$\cot(\frac{\pi}{2} - \theta)$

In trigonometry:

$\cot(\frac{\pi}{2} - \theta) = \tan(\theta)$

Hence:

$\cot(\frac{\pi}{2} - \theta) = 9$

Solving (d):

$\csc^2(\theta)$

This is calculated as:

$\csc^2(\theta) = (\csc(\theta))^2$

$\csc^2(\theta) = (\frac{1}{\sin(\theta)})^2$

Where:

$\sin(\theta) = \frac{Opposite}{Hypotenuse}$

$\sin(\theta) = \frac{9}{\sqrt{82}}$

So:

$\csc^2(\theta) = (\frac{1}{\frac{9}{\sqrt{82}}})^2$

$\csc^2(\theta) = (\frac{\sqrt{82}}{9})^2$

$\csc^2(\theta) = \frac{82}{81}$

4 0

3 years ago

Give a counterexample to disprove the statement "all squares are congruent"

kakasveta [241]

Give a counterexample to disprove the statement all squares are congruent

4 0

3 years ago

The formula for the nth term of an arithmetic sequence can be found using the formula a Subscript n Baseline = a Subscript 1 Bas

Gnoma [55]

The equation of nth term will be written as for n as will be ( $\rm a_n$ - a₁ + d) / d. Then the correct option is D.

The missing options are attached to the picture given below.

<h3>What is a sequence?</h3>

A sequence is a list of elements that have been ordered in a sequential manner, such that members come either before or after.

The formula for the nth term of an arithmetic sequence can be found using the formula given below.

$\rm a_n = a_1 + (n-1)d$

Then arrange the equation for n, we have

$\begin{aligned} \rm a_n - a_1 & \rm = nd - d\\\\\rm a_n - a_1 + d & \rm =nd\\\\\rm n & \rm = \dfrac{a_n - a_1 + d}{d} \end{aligned}$

Then the correct option is D.

More about the sequence link is given below.

brainly.com/question/21961097

#SPJ1

6 0

2 years ago