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3 years ago

Need number 15 please help! NO LINKS!!!!!1

Mathematics

1 answer:

daser333 [38]3 years ago

8 0

Answer:

<u>All sides of a rhombus are equal.</u>

9a - 18 = 3a + 15
6a = 33
3a = 16.5

VW = 16.5 + 15 = 31.5

Diagonal of a rhom<em>bus are perpendicular to each other.</em>
<em>Diagonals are angle bisectors.</em>
<em>Adjacent angles are supplementary.</em>

m∠XZW = 10b - 5
10b - 5 = 90
10b = 95
b = 9.5

m∠WVY = 4b + 10 = 4*9.5 + 10 = 48°

m∠VWX = 180° - 48° = 132°
m∠WYX = 1/2m∠VWX = 1/2(132°) = 66°

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Identify the graph of the line 3x-7y=-21

AveGali [126]

Y = (3x-21)/7
the picture is the graph

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4 years ago

For the function y=x^2-4x-5, perform the followingtasks:

lbvjy [14]

Answer:

a. $x^2-4x-5= \left(x-2\right)^2-9$ .

b. The axis of symmetry for ${\left(x - 2\right)^{2}} - 9$ is $x=2$ .

Step-by-step explanation:

a. The vertex form of a quadratic is given by $y=a(x-h)^2+k$ , where (h, k) is the vertex.

To convert from $y=x^2-4x-5$ form to vertex form you use the process of completing the square.

Step 1: Write $x^2-4x-5$ in the form $x^2+2ax+a^2$ . Add and subtract 4:

$x^{2} - 4 x - 5=x^{2} - 4 x + {\left(4\right)} - {4} - 5$

Step 2: Complete the square $x^2+2ax+a^2=\left(x+a\right)^2$

${\left(x^{2} - 4 x + 4\right)} - 9={\left(x - 2\right)^{2}} - 9$

b. The graph of a quadratic function is a parabola. The axis of symmetry of a parabola is a vertical line that divides the parabola into two congruent halves. The axis of symmetry always passes through the vertex of the parabola. The x-coordinate of the vertex is the equation of the axis of symmetry of the parabola.

For a quadratic function in standard form, $y=a(x-h)^2+k$ , the axis of symmetry is $x=h$ .

The axis of symmetry for ${\left(x - 2\right)^{2}} - 9$ is $x=2$ .

Look at the graph shown below.

5 0

3 years ago

Help with both plz I’ll mark brainliest

LekaFEV [45]

Answer:

(1,6) is not a solution and I think the second one is: c I think

Step-by-step explanation:

5 0

3 years ago

PLLLLEEEEEEAAASSSSSSSSEEEE

mrs_skeptik [129]

Given:

Line a passes through (2, 10) and (4, 13).

Line b passes through (4, 9) and (6, 12).

Line c passes through (2, 10) and (4, 9).

To find:

Which of the lines, if any are perpendicular.

Solution:

If a line passes through two points, then the slope of line is

$m=\dfrac{y_2-y_1}{x_2-x_1}$

Line a passes through (2, 10) and (4, 13). So, slope of this line is

$m_a=\dfrac{13-10}{4-2}=\dfrac{3}{2}$

Line b passes through (4, 9) and (6, 12). So, slope of this line is

$m_b=\dfrac{12-9}{6-4}=\dfrac{3}{2}$

Line c passes through (2, 10) and (4,9). So, slope of this line is

$m_c=\dfrac{9-10}{4-2}=\dfrac{-1}{2}$

Product of slopes of to perpendicular lines is -1.

$m_a\cdot m_b=\dfrac{3}{2}\times \dfrac{3}{2}=\dfrac{9}{4}\neq -1$

$m_b\cdot m_c=\dfrac{3}{2}\times \dfrac{-1}{2}=\dfrac{-3}{4}\neq -1$

$m_a\cdot m_c=\dfrac{3}{2}\times \dfrac{-1}{2}=\dfrac{-3}{4}\neq -1$

Therefore, any of these lines are not perpendicular to each other.

8 0

3 years ago

Which number produces an irrational number when added to 3/4?

S_A_V [24]

Any irrational number produces an irrational number when added to 3/4.

This is because 3/4 is rational (it can be represented as a ratio of two integers). You can get an irrational number only when you add rational to irrational (because rational to rational produces a rational sum).

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4 years ago